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AysviL [449]
3 years ago
14

You wish to roll a 7 on and 8-sided die. What is the probability that the first 7 happens on the 3rd, 4th, or 5th try?

Mathematics
1 answer:
professor190 [17]3 years ago
7 0

Answer:

0.15%

Step-by-step explanation:

The probability of rolling a 7 on a 8-sided die will always be:

1/8

We know that for the first two tries that there is 7/8 chance that the die will land on anything but a 7:

=(7/8)\cdot{(7/8)}=49/64=0.77

For the die to land on a 7 the 3rd, 4th and 5th try is:

=(1/8)\cdot{(1/8)}\cdot{(1/8)}=1/512

The probability is therefore:

{1/512)\cdot{(49/64)}=49/32768=0.00149

The probability that the die will land on a 7 not on the first and second try but on the 3rd, 4th and 5th try is 0.15%

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The augmented matrix of a system of equations has been transformed to an equivalent matrix in​ row-echelon form. Using​ x, y
jenyasd209 [6]

Answer: The system of equations is:

x + 2y + 2 = 4

y - 3z = 9

z = - 2

The solution is: x = -22; y = 15; z = -2;

Step-by-step explanation: ONe way of solving a system of equations is using the Gauss-Jordan Elimination.

The method consists in transforming the system into an augmented matrix, which is writing the system in form of a matrix and then into a <u>Row</u> <u>Echelon</u> <u>Form,</u> which satisfies the following conditions:

  • There is a row of all zeros at the bottom of the matrix;
  • The first non-zero element of any row is 1, which called leading role;
  • The leading row of the first row is to the right of the leading role of the previous row;

For this question, the matrix is a Row Echelon Form and is written as:

\left[\begin{array}{ccc}1&2&2\\0&1&3\\0&0&1\end{array}\right]\left[\begin{array}{ccc}4\\9\\-2\end{array}\right]

or in system form:

x + 2y + 2z = 4

       y + 3z = 9

               z = -2

Now, to determine the variables:

z = -2

y + 3(-2) = 9

y = 15

x + 30 - 4 = 4

x = - 22

The solution is (-22,15,-2).

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3 years ago
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horrorfan [7]

Answer:

3

Step-by-step explanation:

you have to solve for x then you can find the coeeffiecnt

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a local school has a gymnasium that is 48ft long, 36ft wide with an 18ft high ceiling. the school maintenance staff is painting
pshichka [43]

Answer:

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These are rectangles we can easily calculate the area:

longer walls: 2 (48 * 18) = 2 * 864 = 1,728 sq ft

shorter walls: 2 (36 x 18) = 2 * 648 = 1,296 sq ft

Total of the walls: 1,728 + 1,296  = 3,024 sq ft.

Now, we assume they'll paint everything and that there are no windows.

Each can covers 400 sq ft.

If we divide 3,024 by 400 we get 7.56

So, they'll need to buy 8 cans of paint to do the job.  In such problems, we always round up, otherwise they wouldn't have enough paint.

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