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kirill115 [55]
3 years ago
6

Explain the answer boy step -7x-3x+2=-8x-8 -8-x=x-4x

Mathematics
1 answer:
brilliants [131]3 years ago
3 0
1. simplify -7x-3x+2 to -10x+2
 -10x+2=-8x-8
2. add 10x to both sides
2=-8x-8+10x
3. simplify -8x-8+10x to 2x-8
2=2x-8
4. add 8 to both sides
2+8=2x
5. simplify 2+8 to 10
10=2x
6. divide both sides by 2
10/2=x
7. simplify 10/2 to 5
5=x
8. switch sides
x=5

1. simplify x-4x to -3x
-8-x=-3x
2. add x to both sides
-8=-3x+x
3. simplify -3x+x to -2x
-8=-2x
4. divide both sides by -2
-8/-2=x
5. two negatives make a positive
8/2=x
6. simplify 8/2 to 4
4=x
7. switch sides
x=4
hope this helps
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54394 plus 13768<br><br><br> Thank you
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A contractor records all of the bedroom areas, in square feet, of a five-bedroom house as: 100, 100, 120, 120, 180 What is the v
kifflom [539]
The variance is the total of the squared distances of the given data from the mean. 

This can be calculated through the equation,
        
                            σ² = summation of X² / N  - μ²

where σ² is the variance X's are the data, N is the number of terms, and μ is the mean.

   summation of X² = 100² + 100² + 120² + 120² + 180² = 81200
                          N = 5
                                        μ = (100 + 100 + 120 + 120 + 180) / 5
                                         μ = 124

Substituting these values to the equation for variance,
                                 
                              σ² = (81200/5) - 124² = 864

Thus, the variance is equal to 864. 
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The graph below represents the solution set of which inequality?
natulia [17]

Answer:

option: B (x^2+2x-8) is correct.

Step-by-step explanation:

We are given the solution set as seen from the graph as:

(-4,2)

1)

On solving the first inequality we have:

x^2-2x-8

On using the method of splitting the middle term we have:

x^2-4x+2x-8

⇒  x(x-4)+2(x-4)=0

⇒ (x+2)(x-4)

And we know that the product of two quantities are negative if either one of them is negative so we have two cases:

case 1:

x+2>0 and x-4

i.e. x>-2 and x<4

so we have the region as:

(-2,4)

Case 2:

x+2 and x-4>0

i.e. x<-2 and x>4

Hence, we did not get a common region.

Hence from both the cases we did not get the required region.

Hence, option 1 is incorrect.

2)

We are given the second inequality as:

x^2+2x-8

On using the method of splitting the middle term we have:

x^2+4x-2x-8

⇒ x(x+4)-2(x+4)

⇒ (x-2)(x+4)

And we know that the product of two quantities are negative if either one of them is negative so we have two cases:

case 1:

x-2>0 and x+4

i.e. x>2 and x<-4

Hence, we do not get a common region.

Case 2:

x-2 and x+4>0

i.e. x<2 and x>-4

Hence the common region is (-4,2) which is same as the given option.

Hence, option B is correct.

3)

x^2-2x-8>0

On using the method of splitting the middle term we have:

x^2-4x+2x-8>0

⇒ x(x-4)+2(x-4)>0

⇒ (x-4)(x+2)>0

And we know that the product of two quantities are positive if either both of them are negative or both of them are positive so we have two cases:

Case 1:

x+2>0 and x-4>0

i.e. x>-2 and x>4

Hence, the common region is (4,∞)

Case 2:

x+2 and x-4

i.e. x<-2 and x<4

Hence, the common region is: (-∞,-2)

Hence, from both the cases we did not get the desired answer.

Hence, option C is incorrect.

4)

x^2+2x-8>0

On using the method of splitting the middle term we have:

x^2+4x-2x-8>0

⇒ x(x+4)-2(x+4)>0

⇒ (x-2)(X+4)>0

And we know that the product of two quantities are positive if either both of them are negative or both of them are positive so we have two cases:

Case 1:

x-2 and x+4

i.e. x<2 and x<-4

Hence, the common region is: (-∞,-4)

Case 2:

x-2>0 and x+4>0

i.e. x>2 and x>-4.

Hence, the common region is: (2,∞)

Hence from both the case we do not have the desired region.

Hence, option D is incorrect.




5 0
3 years ago
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