A worker can assemble 3 shelf units each hr. During the 5th hr...so the shift has been going on for 5 hrs...at 3 units per hr = (3 * 5) = 15 units assembled during the shift....and if there was 115 units in the warehouse, then that means before the shift, there were (115 - 15) = 100 units assembled <=
(x-4)² + (x-2)² = x²
(x² - 8x + 16 ) + (x² - 4x + 4) = x
2x² -12x + 20 = x
2x²-12x + 20 - x = 0
2x² - 13x + 20 = 0
(2x-5) (x-4) = 0
2x-5 = 0
2x = 5
x = ⁵/₂
x-4 = 0
x = 4
so x₁ = ⁵/₂ , and x₂ = 4
Answer:
d = - 8
Step-by-step explanation:
3(d-8) - 5 = 9(d+2) + 1
3d-24 - 5 = 9d+18 + 1
3d - 29 = 9d + 19
9d - 3d = -29 - 19
6d = - 48
6d / 6 = -48/6
d = -8
Answer:
2/9
Step-by-step explanation:
The zeros of the function are x=2,-9
