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mote1985 [20]
3 years ago
14

Keisha is riding her bike on Bayview Bike path. Keisha‘s bike got a flat tire 2/3 of the way down the path, so she had to stop.

How far did Keisha ride.
Mathematics
1 answer:
Leona [35]3 years ago
3 0

Answer:

\frac{7}{12} miles.

Step-by-step explanation:

Please consider the complete question.

Bay View Bike Path is 7/8 miles. Keisha is riding her bike on Bay View bike path. Keisha's bike got a flat tire 2/3 of the way down the oath and she had to stop. How far did Keisha ride?

To find the distance covered by Keisha while riding the bike, we need to find 2/3 of 7/8 miles.

\text{Distance that Keisha ride}=\frac{2}{3}\times \frac{7}{8}

\text{Distance that Keisha ride}=\frac{1}{3}\times \frac{7}{4}

\text{Distance that Keisha ride}=\frac{1\times 7}{3\times 4}

\text{Distance that Keisha ride}=\frac{7}{12}

Therefore, Keisha ride \frac{7}{12} miles.

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amid [387]

If the company orders 27 boxed lunches from a deli for $245.70 and each boxed lunch costs the same amount then the unit cost of each boxed lunched is $9.1.

<h3>What is the unit cost of each boxed lunch?</h3>

Given that;

  • 27 boxed lunches from a deli cost $245.70
  • Cost of 1 box = ?

To determine the unit cost of each boxed lunch, we say;

Cost of each box = $245.70 ÷ 27

Cost of each box = $9.1

Hence, if the company orders 27 boxed lunches from a deli for $245.70 and each boxed lunch costs the same amount then the unit cost of each boxed lunched is $9.1

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Given the equation xy+4y=3x-2 show that y is a function of x and determine the domain in interval notation.
Mekhanik [1.2K]
First, the equation has to be rearranged so that y will be isolated on the left-hand side of the equation.


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This form is a rational function which is of course a function. All values of x are possible, except for x when y becomes undefined, thus the domain should be x /= -4. In interval notation, (-inf, -4) U (-4, inf).


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Step-by-step explanation:

7 0
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Answer:

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Step-by-step explanation:

The given system of equations is;

y=-5x-8...(1)

and

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The solution is;

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