We can write the argument of the logarithm as a power of 6:
![\log_6\dfrac1{36}=\log_6\dfrac1{6^2}=\log_66^{-2}](https://tex.z-dn.net/?f=%5Clog_6%5Cdfrac1%7B36%7D%3D%5Clog_6%5Cdfrac1%7B6%5E2%7D%3D%5Clog_66%5E%7B-2%7D)
Then using the property that
, we get
![\log_6\dfrac1{36}=-2\log_66](https://tex.z-dn.net/?f=%5Clog_6%5Cdfrac1%7B36%7D%3D-2%5Clog_66)
and since
, we have
, so the value of this expression is simply -2.
Take 38,000 minus 6,840 and then you got your answer
Hello again,
We know that the clock has rectangular shapes, and the clock face is circle.
Area of the clock is:
15×8=120 square inches
To find the area of the circle:
πr^2. However, we did not know the radius yet, but we had circumference of the circle which is 6 inches
C=2πr
6=2πr
Divided 2 from both side
3=πr
Divide π or 3.14 from both side
r≈1 inches
Area of the clock face is:
1×1×3.14
≈3.14.
To find the area of the clock that does not covered with clock face take:
120-3.14=116.86 square inches. Hope it help!
Answer:
i know its c
Step-by-step explanation:
i had this question yesterday
The answer is C. 5 1/2 hours. Hope this helped. :)