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IgorLugansk [536]
4 years ago
14

Which is the range of the function f(x) = 1/7 (9)x

Mathematics
2 answers:
elena-s [515]4 years ago
7 0

Answer:

Interval notation for range is (0, ∞)

Step-by-step explanation:

f(x)= 1/7 (9)^x

f(x)= \frac{1}{7} (9)^x

Range is the set of y values for which the function is defined

For all positive and negative values for x the value of y is always positive

so the range y value is greater than 0

Range of the function is y values greater than 0

y>0

Interval notation for range is (0, ∞)

adelina 88 [10]4 years ago
4 0
Range of f(x) = 1/7(9)x =
All real numbers greater than 0. 

♥
Hope I helped ♥
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What is the solution to sqrt 17-x=x+3? Show your work.
snow_lady [41]

Answer:

x=1

Step-by-step explanation:

Remember:

(\sqrt[n]{a})^n=a\\\\(a+b)=a^2+2ab+b^2

Given the equation \sqrt{17-x}=x+3, you need to solve for the variable "x" to find its value.

You need to square both sides of the equation:

(\sqrt{17-x})^2=(x+3)^2

17-x=(x+3)^2

Simplifying, you get:

17-x=x^2+2(x)(3)+3^2\\\\17-x=x^2+6x+9\\\\x^2+6x+9+x-17=0\\\\x^2+7x-8=0

Factor the quadratic equation. Find two numbers whose sum be 7 and whose product be -8. These are: -1 and 8:

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Then:

x_1=1\\x_2=-8

Let's check if the first solution is correct:

\sqrt{17-(1)}=(1)+3

4=4 (It checks)

Let's check if the second solution is correct:

\sqrt{17-(-8)}=(-8)+3

5\neq-5 (It does not checks)

Therefore, the solution is:

x=1

3 0
3 years ago
Help me to solve this.<br><br>x + 5 = 5
Ivenika [448]
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Step by step explanation:
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Step-by-step explanation:

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Order from greatest to least 5.249;5.43;5.340;5.209
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