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4 years ago

Which is the range of the function f(x) = 1/7 (9)x

Mathematics

2 answers:

elena-s [515]4 years ago

7 0

Answer:

Interval notation for range is (0, ∞)

Step-by-step explanation:

f(x)= 1/7 (9)^x

$f(x)= \frac{1}{7} (9)^x$

Range is the set of y values for which the function is defined

For all positive and negative values for x the value of y is always positive

so the range y value is greater than 0

Range of the function is y values greater than 0

y>0

Interval notation for range is (0, ∞)

adelina 88 [10]4 years ago

4 0

Range of f(x) = 1/7(9)x =
All real numbers greater than 0.

♥ Hope I helped ♥

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Simplify: √27x^2y^2 A) 27xy B) 3xy C) 3xy√3 D) xy√27

iren2701 [21]

Answer:

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Hence, option C is correct.

Step-by-step explanation:

Given the expression

$\sqrt{27x^2y^2}$

simplifying the expression

$\sqrt{27x^2y^2}=\sqrt{27}\sqrt{x^2}\sqrt{y^2}$

Apply radical rule: $\sqrt{a^2}=a,\:\quad \mathrm{\:assuming\:}a\ge 0$

$=\sqrt{27}x\sqrt{y^2}$

Apply radical rule: $\sqrt{a^2}=a,\:\quad \mathrm{\:assuming\:}a\ge 0$

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Apply radical rule: $\sqrt{a^2}=a,\:\quad \mathrm{\:assuming\:}a\ge 0$

$=3xy\:\sqrt{3}$

Therefore,

$\sqrt{27x^2y^2}=3xy\:\sqrt{3}$

Hence, option C is correct.

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