The rate at which the ice changes is -3/8 lb per hr
<h3>What is the rate the ice changes?</h3>
The given parameters are:
Changes =1 3/4 lb to 1/4 lb
Time = 1/4 hr.
The rate the ice changes is calculated as:
Rate = Change/Time
So, we have
Rate = (1/4 lb - 1 3/4 lb)/(1/4 hr)
Evaluate the difference
Rate = (-1 1/2 lb)/(1/4 hr)
Evaluate the quotient
Rate = -3/8 lb per hr
Hence, the rate at which the ice changes is -3/8 lb per hr
Read more about rates at:
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So you would use a frequency table when they are asking for how many times does this come in to the play. For example , let's say there was a play and 2 different characters we're in it the cat came out 3 times and the the dog came out 5 times. Which character came out more times.
The answer is 20!
−100×(−20)=?
2000
Answer:
The graph in the attached figure
Step-by-step explanation:
we have
------>inequality A
The solution of the inequality A is the shaded area above the dashed line 
The y-intercept of the dashed line is (0,6)
The x-intercept of the dashed line is (-24,0)
The slope of the dashed line is positive m=1/4
------>inequality B
The solution of the inequality B is the shaded area above the dashed line 
The y-intercept of the dashed line is (0,-1)
The x-intercept of the dashed line is (0.5,0)
The slope of the dashed line is positive m=2
The solution of the system of inequalities is the shaded area between the two dashed lines
using a graphing tool
see the attached figure