△DEF has vertices D (2,2), E (-2,-1), and F (-3,5). Complete the following charts indicating the location of △D′E′F′ and △D″E″F″
.△DEF is reflected in the y-axis. Then it is translated along the vector ⟨3,−5⟩. Enter your answers as points using parenthesis and commas. Do not use any spaces.
1 answer:
Reflecting DEF on the y-axis gives the following coordinates of D'E'F' as follows
the coordinate of D' (-2, 2)
the coordinate of E' (2, -1)
the coordinate of F' (3, 5)
Translating D'E'F' by the vector (3, -5) gives the following coordinate of D''E''F'' as follows
the coordinate of D'' (-2+3, 2-5) = (1, -3)
the coordinate of E'' (2+3, -1-5) = (5, -6)
the coordinate of F'' (3+3, 5-5) = (6, 0)
The diagram below shows the transformation of triangle DEF
the coordinate of D' (-2, 2)
the coordinate of E' (2, -1)
the coordinate of F' (3, 5)
Translating D'E'F' by the vector (3, -5) gives the following coordinate of D''E''F'' as follows
the coordinate of D'' (-2+3, 2-5) = (1, -3)
the coordinate of E'' (2+3, -1-5) = (5, -6)
the coordinate of F'' (3+3, 5-5) = (6, 0)
The diagram below shows the transformation of triangle DEF
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<em><u>An inequality that shows the distance Johnathan could of ran any day this week is:</u></em>
<em><u>Solution:</u></em>
Let "x" be the distance Johnathan can run any day of this week
Given that,
Johnathan ran 5 days this week. The most he ran in one day was 3.5 miles
Therefore,
Number of days ran = 5
The most he ran in 1 day = 3.5 miles
Thus, the maximum distance he ran in a week is given as:
The maximum distance he ran in a week is 17.5 miles
If we let x be the distance he can run any day of this week then, we get a inequality as:
If we let y be the total distance he can travel in a week then, we may express it as,