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dybincka [34]
4 years ago
11

The polynomial p(x)=x^5-9x^4+13x^3+57x^2-86x-120 has how many zeros

Mathematics
2 answers:
natita [175]4 years ago
8 0
It has a total of 5 zeros
lutik1710 [3]4 years ago
7 0
The polynomial p(x) = x^5 − 9x^4 + 13x^3 + 57x^2 − 86x − 120 has a total of 5 zeroes. It can have a maximum of 3 positive real roots and a maximum of 2 negative real roots.
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