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4 years ago

The polynomial p(x)=x^5-9x^4+13x^3+57x^2-86x-120 has how many zeros

Mathematics

2 answers:

natita [175]4 years ago

8 0

It has a total of 5 zeros

lutik1710 [3]4 years ago

7 0

The polynomial p(x) = x^5 − 9x^4 + 13x^3 + 57x^2 − 86x − 120 has a total of 5 zeroes. It can have a maximum of 3 positive real roots and a maximum of 2 negative real roots.

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The number of fish in a lake is decreasing by 400 every year, as described by the function below.

SVEN [57.7K]

The number of fish in the lake follows an arithmetic sequence

The number of fish in the lake the second year is 7800, and it is represented by f(2)

The model of the number of fish is given as:

$\mathbf{f(n + 1) = f(n) - 400}$

Such that:

$\mathbf{f(1) = 8200}$

Set n = 1, to calculate f(2)

Substitute 1 for n in the given model $\mathbf{f(n + 1) = f(n) - 400}$

So, we have:

$\mathbf{f(n + 1) = f(n) - 400}$

$\mathbf{f(1 + 1) = f(1) - 400}$

Simplify, by adding 1 and 1

$\mathbf{f(2) = f(1) - 400}$

Substitute 8200 for f(1)

$\mathbf{f(2) = 8200 - 400}$

Subtract 400 from 8200

$\mathbf{f(2) = 7800}$

Hence, the value of f(2) is 7800

Read more about arithmetic sequence at:

brainly.com/question/25759461

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