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This question asks for a line that passes through the point P(<span>– 3, 0</span>), whose slope is m = <span>– 2.
The equation of this line is
![\mathsf{y-y_P=m\cdot (x-x_P)}\quad\longleftarrow\quad\textsf{(point-slope formula)}\\\\ \mathsf{y-0=-2\cdot (x-(-3))}\\\\ \mathsf{y=-2\cdot (x+3)}\\\\\\\ \mathsf{y=-2x-6}\quad\longleftarrow\quad\textsf{(slope-intersect form)}\\\\\\ \mathsf{2x+y=-6}\quad\longleftarrow\quad\textsf{(standard form)}](https://tex.z-dn.net/?f=%5Cmathsf%7By-y_P%3Dm%5Ccdot%20%28x-x_P%29%7D%5Cquad%5Clongleftarrow%5Cquad%5Ctextsf%7B%28point-slope%20formula%29%7D%5C%5C%5C%5C%0A%5Cmathsf%7By-0%3D-2%5Ccdot%20%28x-%28-3%29%29%7D%5C%5C%5C%5C%0A%5Cmathsf%7By%3D-2%5Ccdot%20%28x%2B3%29%7D%5C%5C%5C%5C%5C%5C%5C%0A%5Cmathsf%7By%3D-2x-6%7D%5Cquad%5Clongleftarrow%5Cquad%5Ctextsf%7B%28slope-intersect%20form%29%7D%5C%5C%5C%5C%5C%5C%0A%5Cmathsf%7B2x%2By%3D-6%7D%5Cquad%5Clongleftarrow%5Cquad%5Ctextsf%7B%28standard%20form%29%7D)
I hope this helps. =)
Tags: <em>point slope intersect line equation analytical geometry linear algebra</em>
</span>
Its 163 bc their corresponding angles i think
Answer:
ik the answer
Step-by-step explanation:
just multiply 5 x 53.42 and the answer is 267.1
Answer:
θ = 36.9°
Step-by-step explanation:
Trigonometric ratios in a right triangle will be,
Sinθ =
= ![\frac{\text{AC}}{\text{AB}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7BAC%7D%7D%7B%5Ctext%7BAB%7D%7D)
Cosθ =
= ![\frac{\text{BC}}{\text{AB}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7BBC%7D%7D%7B%5Ctext%7BAB%7D%7D)
Tanθ =
= ![\frac{\text{AC}}{\text{BC}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7BAC%7D%7D%7B%5Ctext%7BBC%7D%7D)
In the picture attached,
Given sides are,
AB = 5 and BC = 4
Therefore, to find the given angle θ only Cosine will be applicable.
Cos θ = ![\frac{\text{BC}}{\text{AB}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7BBC%7D%7D%7B%5Ctext%7BAB%7D%7D)
= ![\frac{4}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B5%7D)
θ = ![Cos^{-1}(0.8)](https://tex.z-dn.net/?f=Cos%5E%7B-1%7D%280.8%29)
θ = 36.87°
θ ≈ 36.9°