[tex]440 \: ( 1 + \frac{5t}{46 + \: {t}^{2} } ) \\ 440 \: ( \frac{6t}{46 {t}^{2} } ) \: ( \: multiply \: 440 \times 6t) \\ \frac{2640}{46} \\ = 57.39 or 57.30

8 0

3 years ago

Which employer is the least likely for careers in Energy?

Verdich [7]

Self employed ....,,,

7 0

4 years ago

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What is the factored form of the expression?<br><br> d^2 = 36d + 324

Aleonysh [2.5K]

Answer:

(x-43.45)(x+7.45)=0.

Step-by-step explanation:

We have the quadratic equation $d^{2}=36d+324$ i.e. $d^{2}-36d-324=0$

Now, the roots of the quadratic equation $ax^{2}+bx+c=0$ are given by $x=\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}$

So, from the given equation, we have,

a = 1, b =-36 , c = -324.

Substituting the values in $x=\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}$ , we get,

$x=\frac{36\pm \sqrt{(-36)^{2}-4\times 1\times (-324)}}{2\times 1}$

i.e. $x=\frac{36\pm \sqrt{1296+1296}}{2}$

i.e. $x=\frac{36\pm \sqrt{2592}}{2}$

i.e. $x=\frac{36\pm 50.9}{2}$

i.e. $x=\frac{36+50.9}{2}$ and i.e. $x=\frac{36-50.9}{2}$

i.e. $x=\frac{86.9}{2}$ and i.e. $x=\frac{-14.9}{2}$

i.e. x = 43.45 and x = -7.45

Hence, the factored form of the given expression will be (x-43.45)(x+7.45)=0.

4 0

3 years ago

A set of data points has an equation of y= -1.5 + 2.5x.

loris [4]

But what are the answer choices

4 0

4 years ago

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