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satela [25.4K]
3 years ago
15

4letter blocks ABCD how many different ways can they be arranged in a row

Mathematics
2 answers:
scoray [572]3 years ago
5 0
There are 24 ways.
1234 1243 
<span>1324 1342 </span>
<span>1423 1432 </span>

<span>2134 2143 </span>
<span>2314 2341 </span>
<span>2413 2431 </span>

<span>3124 3142 </span>
<span>3214 3241 </span>
<span>3412 3421 </span>

<span>4123 4132 </span>
<span>4213 4231 </span>
<span>4312 4321 </span>
Zigmanuir [339]3 years ago
4 0
There are 4 letter blocks so you can do 
A) DCBA
B) BCAD
c) CDBA
D) ACDB

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How many terms of series 64+16+4 have the sum 5461\64?
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Subtract 1.05 from a certain number. Multiply the difference by 0.8, add 2.84 to the product then divide the sum by 0.01 and get
artcher [175]
The number is 6.25.

We will set up an equation for this.  Let x be the unknown number.  Subtracting 1.05 from it gives us

(x-1.05)

Multiplying the difference by 0.8 would give us

0.8(x-1.05)

Adding 2.84 to the product would give us

0.8(x-1.05)+2.84

Dividing the sum by 0.01 would give us

[0.8(x-1.05)+2.84]/0.01 = 700

We will start working backward, cancelling the division by 0.01 first by multiplying:

([0.8(x-1.05)+2.84]/0.01)*0.01 = 700*0.01

0.8(x-1.05)+2.84 =7

Subtract 2.84 from both sides:
0.8(x-1.05)+2.84-2.84 = 7-2.84
0.8(x-1.05) = 4.16

Use the distributive property on the left side:
0.8*x - 0.8*1.05 = 4.16
0.8x - 0.84 = 4.16

Add 0.84 to both sides:
0.8x - 0.84+0.84 = 4.16+0.84
0.8x = 5

Divide both sides by 0.8:
0.8x/0.8 = 5/0.8
x = 6.25
5 0
3 years ago
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