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3 years ago

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PLEASE HELP.. on the number line, suppose point E has a coordinates of 3, and EG=11. What are the possible coordinates of point

G? The possible coordinates of point G are

1 answer:

harina [27]3 years ago

7 0

Answer:

it is 8

Step-by-step explanation:

because EG is E+G which is 8+3 which equals 11 so it is 8

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ale4655 [162]

Answer:

Inequality form

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Interval notation

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Find all complex solutions of 7x^2-7x+3=0

Sedaia [141]

Answer:

The complex solutions are

$x = (\frac{7-\sqrt{35} i }{42} , ) x = \frac{7 + \sqrt{35} i }{42})$

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given equation 7 x² - 7 x +3=0

$x = (\frac{-b -\sqrt{b^{2}-4ac } }{2ac} , \frac{-b +\sqrt{b^{2}-4ac } }{2ac})$

Given standard equation

a x² +b x +c =0

a = 7 , b= -7 and c=3

<u><em>Step(ii):-</em></u>

<u><em></em></u> $x = (\frac{-(-7) -\sqrt{(-7)^{2}-4(7)(3) } }{2(7)(3)} , \frac{-(-7) +\sqrt{(-7)^{2}-4(7)(3) } }{2(7)(3)})$ <u><em></em></u>

<u><em></em></u> $x = (\frac{7-\sqrt{(49-84 } }{42} , \frac{7 +\sqrt{(49-84 } }{42})$ <u><em></em></u>

$x = (\frac{7-\sqrt{35i^{2} } }{42} , \frac{7 + \sqrt{35i^{2} } }{42})$

$x = (\frac{7-\sqrt{35} i }{42} , \frac{7 + \sqrt{35} i }{42})$

<u><em></em></u>

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Answer:

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Igoryamba

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3 years ago