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Setler79 [48]
3 years ago
12

PLEASE HELP.. on the number line, suppose point E has a coordinates of 3, and EG=11. What are the possible coordinates of point

G? The possible coordinates of point G are
Mathematics
1 answer:
harina [27]3 years ago
7 0

Answer:

it is 8

Step-by-step explanation:

because EG is E+G which is 8+3 which equals 11 so it is 8

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The line tangent to the graph of g(x) = x^{3}-4x+1 at the point (2, 1) is given by the formula
Usimov [2.4K]

well, about A and D, I just plugged the values on the slope formula of

\bf \begin{array}{llll} g(x)=x^3-4x+1\\ L(x) = 8(x-2)+1 \end{array} \qquad \begin{cases} x_1=1.9\\ x_2=2.1 \end{cases}\implies \cfrac{f(b)-f(a)}{b-a}

for A the values are 8.01 and 8.0, so indeed those "slopes" are close. \textit{\huge \checkmark}

for D the values are -2.25 and 8.0, so no dice on that one.

for B, let's check the y-intercept for g(x), by setting x = 0, we end up g(0) = 0³-4(0)+1, which gives us g(0) = 1.

checking L(x) y-intercept, well, L(x) is in slope-intercept form, thus the +1 sticking out on the far right is the y-intercept, so, dice. \textit{\huge \checkmark}

for C, well, the slope if L(x) is 8, since it's in slope-intercept form, the derivative of g(x) is g'(x) = 3x² - 4, and thus g'(0) = -4, so no dice.

for E, do they intercept at (2,1)?  well, come on now, L(x) is a tangent line to g(x), so that's a must for a tangent. \textit{\huge \checkmark}

for F, we know the slope of the line L(x) is 8, is g'(2) = 8?  let's check

recall that g'(x) = 3x² - 4, so g'(2) = 3(2)² - 4, meaning g'(2) = 8, so, dice. \textit{\huge \checkmark}

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mel-nik [20]

Answer:

y>0 Option D

Step-by-step explanation:

4 0
3 years ago
The perimeter of ABCD is 66 and DC is twice as long as CB how long is a B
Natali5045456 [20]
<span>Length = x Width = 2x
Perimeter = 2 * length + 2 * width
= 2x + 4x
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</span><span>Length = x Width = 2x
Perimeter = 2 * length + 2 * width
= 2x + 4x
= 6x 
6x = 66
x = 11</span>
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3 years ago
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