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Nataly [62]
3 years ago
9

alice rode her bike the same number every day for 17 days she rode a tottle of 68miles during thes 17 days at this rate how mane

y miles did alice ride her bike in one day
Mathematics
2 answers:
s344n2d4d5 [400]3 years ago
7 0
4 miles!

68 divided by 17 = 4
Sedaia [141]3 years ago
6 0

Answer:

the answer is 4

Step-by-step explanation:

just divide 68 by 17

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Select Repeating or Nonrepeating to correctly classify each decimal.
astraxan [27]

Answer:

They all reapeating exept C

Step-by-step explanation:

5 0
3 years ago
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Find the product of z1 and z2, where z1 = 7(cos 40° + i sin 40°) and z2 = 6(cos 145° + i sin 145°).
Oduvanchick [21]
For two complex numbers z_1=re^{i\theta}=r(\cos\theta+i\sin\theta) and z_2=se^{i\varphi}=s(\cos\varphi+i\sin\varphi), the product is

z_1z_2=rse^{i(\theta+\varphi)}=rs(\cos(\theta+\varphi)+i\sin(\theta+\varphi))

That is, you multiply the moduli and add the arguments. You have z_1=7e^{i40^\circ} and z_2=6e^{i145^\circ}, so the product is

z_1z_2=7\times6(\cos(40^\circ+145^\circ)+i\sin(40^\circ+145^\circ)=42(\cos185^\circ+i\sin185^\circ)=42e^{i185^\circ}
3 0
3 years ago
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Y = 4x - 2<br> y = x + 3
mihalych1998 [28]

Answer:

Step-by-step explanation:

x = 1

(x^2-4x+3=0 or sin(x)=1)

x = 1

( x^2-4x+3=0 or sin(x)=1)

3 0
3 years ago
What is the probability of getting either a sum of 5 or at least one 5 in the roll of a pair of dice?
maria [59]
In a throw of 2 fair dice, there are 6*6=36 equiprobability outcomes.

To get a sum of 5, there are 4 ways, (1,4),(2,3),(3,2),(4,1) with probability of 4/36=1/9

To get at least one 5, there are 6+6-1=11 outcomes (note (5,5) has been counted in both, so subtracted from sum).  The probability is 11/36

Since the two events are mutually exclusive (once we have a five, the sum can no longer be 5), we can add the probabilities to get the probability of one event or the other.

P(sum of 5 OR at least one 5)=1/9+11/36=4/36+11/36=15/36=5/9
4 0
3 years ago
A study claims that the combination of vitamin C with vitamin E is more effective for preventing the flu than vitamin C alone. I
victus00 [196]

1) In this study, the control group is the first group of 310 subjects that were instructed to take only 600 mg daily of vitamin C. (Option C; that is, group 1).

2) The study is not Blind (Option C).

In an experimental setup to test a theory, A control group is the set of experimental participants that the theory to be tested isn't applied upon.

In the case of testing a new treatment, the control group is the group that the new treatment isn't administered.

For this question, the experiment was set up to test the effectiveness of a combination of vitamin A and vitamin E in treating flu cases rather than using vitamin C alone. Group A is the only group that only the old treatment alone is applied to; group 1 participants received no dosage of the new combination of treatments to be tested involving vitamins A and E, unlike the two other groups.

It is obvious now why the experimental participants of group 1 are the control group.

2) A blind experiment/study is one in which the participants don't know which group they belong to, whether they are in the control group or the other experimental group. Like in this case, if this was a blind study, the participants wouldn't know which group they belonged to or which treatment is administered to them.

A double-blind experiment/study is one in which both the conductors of the experiment and the participants in the experiment wouldn't know which group any participant is in. The conductors wouldn't know which participants were in the control or treatment group and the participants too wouldn't have an idea whether they are in the control or treatment group.

To learn more about the vitamin visit: brainly.com/question/24324739

#SPJ4

3 0
1 year ago
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