Answer:
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Step-by-step explanation:
rwsnuggdfvg
<span>%Antifreeze=<span><span>V<span>Antifreeze</span></span><span>V<span>Fluid</span></span></span></span>
<span><span>V<span>Fluid</span></span>=<span><span>V<span>Antifreeze</span></span><span>%Antifreeze</span></span></span>
<span><span>V<span>Antifreeze</span></span>=<span>V<span>fluid</span></span>∗%Antifreeze</span>
I want to find the amount of antifreeze in a 15 quart solution with 30% antifreeze
<span><span>V<span>Antifreeze</span></span>=15∗0.30</span> =18/4 quarts of antifreeze
Similarly, I want to find the amount of antifreeze in a 15 quart solution with 35% antifreeze first.
<span><span>V<span>Antifreeze</span></span>=15∗0.35</span> = 21/4 quarts of antifreeze
<span>the difference between 21/4 and 18/4 is 3/4 quarts, which is the amount of pure antifreeze I've added in.
</span><span>
SO the V_fluid I replaced with 3/4 quarts of antifreeze is (3/4)/ 0.35</span>
4 to the 1st is 4
4 to the 2nd is 16
4 to the 3rd is 64
<span>4 to the 4th is 256
hope that helps</span>
102/17 = 6
(6*2)+(17*2) = 46
Hope this helps! :)
That person;s body weight will be 156 Ib. Do 9 3/4 times 1/16 to get you body weight