We will find the inverse of the given functions: y = x + 2 / x-2 (x-2) y = x + 2 -2y + xy = x + 2 -2y + xy = x + 2 x (y - 1) = 2 + 2y x (y - 1) = 2 (y + 1) x = 2 (y + 1) / (y - 1) f (x) ^ - 1 = 2 (x + 1) / (x - 1) The inverse is different. f (x) = x + 1 / x-1 y = x + 1 / x-1 (x-1) y = x + 1 -y + xy = x + 1 x (y - 1) = 1 + y x (y - 1) = (y + 1) x = (y + 1) / (y - 1) f (x) ^ - 1 = (x + 1) / (x - 1) The inverse is the same. Answer: f (x) = x + 1 / x-1 f (x) ^ - 1 = (x + 1) / (x - 1) f (x) = f (x) ^ - 1