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Bingel [31]
2 years ago
11

Danielle will use the instructions in the box below to make a cleaning solution I

Mathematics
1 answer:
matrenka [14]2 years ago
4 0

13 cups of water -- 2 cups of concentrated cleaner  (the ratio is \dfrac{13}{2})

w cups of water -- 5 cups of concentrated cleaner (the ratio is \dfrac{w}{5})

Write a proporion:

\dfrac{13}{2}=\dfrac{w}{5}.

Answer: option A

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The volume of a sphere is 267.95 m2. To the nearest meter, what is the radius of the sphere? Use
Novosadov [1.4K]

Answer:

4m

Step-by-step explanation:

  1. v=4/3 pi r^3
  2. substitute 267.95=4/3×3.14×r^3
  3. 267.95= 12.56r^3/3
  4. multiply by the reciprocal on both sides 64=r^3
  5. find the cuberoot on both sides to remove the cube hence 4=r
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Please help I don't understand this very well<br>*picture*​
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The inequality is 9 less than and equal to 5

The marked area on the line is numbers all below 5 which covers the less than and since it stop directly at 5 it's going to be equal to that as well

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Helpppp<br>What is 25% of 307<br>10<br>|<br>2<br>12<br>1<br>7<br>2​
inna [77]

Answer:

76.75 is 25% of 307

Step-by-step explanation:

5 0
2 years ago
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Eunique scores 20 points during the game. This is eleven more than three-fifths of the points she scored in previous game. How m
Ket [755]

Answer:

Step-by-step explanation:

If we call the points she scored in the last game x, we can actually write out an equation to describe what is being said.  20=11+(3/5)x.  Hopefully that makes sense.  3/5 of the previous score plus 11 is 20.  Anyway, you can just solve this algebraic expression for x.

20=11+(3/5)x subtract 11 from both sides

9 = 3/5 x Multiply both sides by 5

45 = 3x then divide both sides by 3

15 = x And there you go.  

6 0
2 years ago
Find four distinct complex numbers (which are neither purely imaginary nor purely real) such that each has an absolute value of
Luda [366]

Answer:

  • 0.5 + 2.985i
  • 1 + 2.828i
  • 1.5 + 2.598i
  • 2 + 2.236i

Explanation:

Complex numbers have the general form a + bi, where a is the real part and b is the imaginary part.

Since, the numbers are neither purely imaginary nor purely real a ≠ 0 and b ≠ 0.

The absolute value of a complex number is its distance to the origin (0,0), so you use Pythagorean theorem to calculate the absolute value. Calling it |C|, that is:

  • |C| = \sqrt{a^2+b^2}

Then, the work consists in finding pairs (a,b) for which:

  • \sqrt{a^2+b^2}=3

You can do it by setting any arbitrary value less than 3 to a or b and solving for the other:

\sqrt{a^2+b^2}=3\\ \\ a^2+b^2=3^2\\ \\ a^2=9-b^2\\ \\ a=\sqrt{9-b^2}

I will use b =0.5, b = 1, b = 1.5, b = 2

b=0.5;a=\sqrt{9-0.5^2}=2.958\\ \\b=1;a=\sqrt{9-1^2}=2.828\\ \\b=1.5;a=\sqrt{9-1.5^2}=2.598\\ \\b=2;a=\sqrt{9-2^2}=2.236

Then, four distinct complex numbers that have an absolute value of 3 are:

  • 0.5 + 2.985i
  • 1 + 2.828i
  • 1.5 + 2.598i
  • 2 + 2.236i
4 0
3 years ago
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