What groups are working on solving road rage

Ireland Corporation obtained a $40,000 note receivable from a customer on June 30, 2011. The note, along with interest at 6%, is

Paul [167]

Answer:

$39,220

Explanation:

The maturity value of the note receivable on June 30, 2012

= Principal + Interest

= $40,000 + $40,000 x 6%

= $40,000 + $2,400

= $ 42,400

The note is discounted on September 30, 2011. Time period remaining to go till maturity as on September 30, 2011

= 12 - 3 months ( July, Aug and Sep)

= 9 months.

Amount of deduction

= $ 42,400 x 10% x 9/12

= $ 3,180

Finally, the Cash received by Ireland will be

= Maturity value - Discount

= $42,400 - $ 3,180

= $39,220

5 0

3 years ago

ABC, a chain of candy stores, purchases its candy in bulk from its suppliers. For a recent shipment, the company paid $1,500 and

spin [16.1K]

Answer: Option (d) is correct.

Explanation:

Amount paid for candy = $1,500

Items received = 8,500 pieces of candy

Group 1 = 2,500 pieces

Selling price = $0.15 each

sale value = pieces sold × Selling price

= 2,500 × $0.15 each

= $375

Group 2 = 5,500 pieces

Selling price = $0.36 each

sale value = pieces sold × Selling price

= 5,500 × $0.36 each

= $1,980

Group 3 = 500 pieces

Selling price = $0.72 each

sale value = pieces sold × Selling price

= 500 × $0.72 each

= $360

Total sale value = $375 + $1,980 + $360

= $2,715

$Percentage\ of\ sale\ in\ Group\ 2=\frac{Sale\ value}{Total\ sale\ value}\times 100$

$Percentage\ of\ sale\ in\ Group\ 2=\frac{1,980}{2,715}\times 100$

= 72.92%

Proportion of cost for Group 2 = cost × Percentage of sale in Group 2

= $1,500 × 72.92%

= $1,093.8

$cost\ per\ unit= \frac{cost}{total\ units}$

$cost\ per\ unit= \frac{1,093.8}{5,500}$

= $0.1988

= $0.20(approx)

4 0

3 years ago

You have $130,000 to invest in a portfolio containing Stock X and Stock Y. Your goal is to create a portfolio that has an expect

Finger [1]

Answer:

Let X be the amount invested in stock A

Let 1-X be the amount invested in stock B

Expected rate = (Required rate of X* X) + (Required ratebof Y * (1-X))

0.146 = (0.128 * X) + (0.078 * (1-X))

0.146 = 0.128X + 0.078 - 0.078X

0.146 - 0.078 = 0.128X - 0.078X

X = 0.068/0.05

X = 1.36

Amount to be invested in Stick X = $130,000 * 1.36

= $176,000

Amount to be invested in Stock Y = (1-X) * Available amount

= (1-1.36) * $130,000

= $46,800

Therefore, the amount to be invested in Stick Y = -$46,800

Calculation of the portfolio beta

bp = w1b1 + w2b2 + ........ + wnbn

bp = (1.36*1.3) + ((-0.36) * 1.05)

bp = 1.768 - 0.378

bp = 1.29

Therefore, the portfolio beta is 1.39

7 0

3 years ago

What are the two most popular ways people make networking contacts?

Semmy [17]

Answer:

Explanation:

Every contact you meet should lead you to new contacts. That's why it's called networking – just like a net, every connection leads off in two or more directions. Your contacts fall into two groups: those who you immediately know might be able to help you, and those who you don't see any point in talking to.

5 0

2 years ago

According to a 2018 article in Esquire magazine, approximately 70% of males over age will develop cancerous cells in their prost

yaroslaw [1]

Answer:

a) Probability of prostrate cancer given a positive test is P(C|+) = 0.0213

b) Probability of cancer given a negative test is P(C|-) = 0.0161

c) Probability of prostrate cancer given a positive test is P(C|+) = 0.3137

d) Probability of cancer given a negative test is P(C|-) = 0.2553

Explanation:

Probability male patient has prostate cancer, P(C) = 0.02

Probability male patient does not have prostrate cancer P(C') = 1 - 0.02 = 0.98

Probability of a positive test given there is no cancer, i.e. P(false positive) = P(+|C') = 0.75

P(negative test given there is cancer) = P(false negative) = P(-|C) = 0.2

P(negative test given there is no cancer) is the complement of P(+|C') = P(-|C') = 1 - 0.75 = 0.25

Probability of positive test given there is prostrate cancer, P(+|C) is the complement of P(-|C), = 1 - 0.2 = 0.8.

a) Probability of prostrate cancer given a positive test is P(C|+)

According to Baye's theorem, P(C|+) = P(+|C)P(C)/P(+)

For P(+), we use the Law Of Total Probability: P(+) = P(+|C)P(C) + P(+|C')P(C')

P(+) = (0.8 * 0.02) + (0.75 * 0.98) = 0.751

Therefore, P(C|+) = P(+|C)P(C)/P(+)

P(C|+) = (0.8 * 0.02)/0.751 = 0.0213

b) Probability of cancer given a negative test is P(C|-)

According to Baye's theorem, P(C|-) = P(-|C)P(C)/P(-)

P(-) = P(-|C)P(C) + P(-|C')P(C')

P(-) = (0.2 * 0.02) + (0.25 * 0.98) = 0.249

Therefore, P(C|-) = (0.2 * 0.02)/0.249

P(C|-) = 0.0161

Part 2: Given the following;

Probability male patient has prostate cancer, P(C) = 0.3

Probability male patient does not have prostrate cancer P(C') = 1 - 0.3 = 0.70

Probability of a positive test given there is no cancer, i.e. P(false positive) = P(+|C') = = 0.75

P(negative test given there is cancer) = P(false negative) = P(-|C) = 0.2

P(negative test given there is no cancer) is the complement of P(+|C') = P(-|C') = 1 - 0.75 = 0.25

Probability of positive test given there is prostrate cancer, P(+|C) is the complement of P(-|C), = 1 - 0.2 = 0.8.

c) Probability of prostrate cancer given a positive test is P(C|+)

According to Baye's theorem, P(C|+) = P(+|C)P(C)/P(+)

For P(+), we use the Law Of Total Probability: P(+) = P(+|C)P(C) + P(+|C')P(C')

P(+) = (0.8 * 0.3) + (0.75 * 0.7) = 0.751

Therefore, P(C|+) = P(+|C)P(C)/P(+)

P(C|+) = (0.8 * 0.3)/0.765 = 0.3137

d) Probability of cancer given a negative test is P(C|-)

According to Baye's theorem, P(C|-) = P(-|C)P(C)/P(-)

P(-) = P(-|C)P(C) + P(-|C')P(C')

P(-) = (0.2 * 0.3) + (0.25 * 0.7) = 0.235

Therefore, P(C|-) = (0.2 * 0.3)/0.235

P(C|-) = 0.2553

4 0

3 years ago