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Kamila [148]
3 years ago
15

Ireland Corporation obtained a $40,000 note receivable from a customer on June 30, 2011. The note, along with interest at 6%, is

due on June 30, 2012. On September 30, 2011, Ireland discounted the note at Cloverdale bank. The bank's discount rate is 10%. What amount of cash did Ireland receive from Cloverdale Bank
Business
1 answer:
Paul [167]3 years ago
5 0

Answer:

$39,220

Explanation:

The maturity value of the note receivable on June 30, 2012

= Principal + Interest

= $40,000 + $40,000 x 6%

= $40,000 + $2,400

= $ 42,400

The note is discounted on September 30, 2011. Time period remaining to go till maturity as on September 30, 2011

= 12 - 3 months ( July, Aug and Sep)

= 9 months.

Amount of deduction  

= $ 42,400 x 10% x 9/12

= $ 3,180

Finally, the Cash received by Ireland will be

= Maturity value - Discount

= $42,400 - $ 3,180

= $39,220

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Both supply and demand concepts rest on the relationship between quantity supplied or demanded.
Rashid [163]

Answer:

False

Explanation:

Both supply and demand concepts rest on the relationship between price and quantity.

Quantity demanded increase when price falls and falls when price increases.

Quantity supplied increases when price increases and falls when price falls.

The demand and supply curve are plotted with price on the y axis and quantity on the x axis.

I hope my answer helps you

7 0
3 years ago
A new alloy can be produced by Process A, which costs $200,000 to implement. The operating cost will be $10,000 per quarter with
Andreyy89

Answer:

Difference between A and B =$42398.5

Process B is better as its PW value is smaller than Process A.

Explanation:

In order to use present worth, both Alternatives must have same time period. Since Process B has 4 years means 16 quarters so we make process A to have 16 quarters two with 2% interest rate per quarter.

Note:

We are going to use Compound Interest tables to simplify our work. Formulas can also be used.

For Process A:

Present value of process A=-200,000-200,000(P/F,2\%,8)-10,000(P/A,2\%,16)+25,000(P/F,2\%,8)+25,000(P/F,2\%,16)

Present value of process A=-200,000-200,000(0.8535)-10,000(13.578)+25,000(0.8535)+25,000(0.7284)

Present value of process A=-$466,932.5

For Process B:

Present value of process B=-250,000-15,000(P/A,2\%,16)+40,000(P/A,2\%,16)

Present value of process B=-250,000-15,000(13.578)+40,000(0.7284)

Present value of process B=-$424,534

Difference between A and B =(-$424,534)-(-$466,932.5)

Difference between A and B =$42398.5

Process B is better as its PW value is smaller than Process A.

7 0
3 years ago
In the weekly computer run to prepare payroll checks, a check was printed for an employee who had been terminated the previous w
Gre4nikov [31]
<h2>A control total for hours worked, prepared from time cards collected by the timekeeping department.</h2>

Explanation:

An employee should get salary only based on the number days / number hours worked for the organization. So the time card will help the organization to solve the problem.

So the time card should be collected and then only the salary needs to be calculated. The salary calculation should take number of leaves (paid / unpaid), permissions and On-duty in to account so that the expected outcome can be achieved.

8 0
3 years ago
Florence is a highly paid fashion consultant who earns $100 per hour. She has 16 hours per day that she can allocate to work or
Dmitry_Shevchenko [17]

Answer:

Please see attachment

Explanation:

Please see attachment

8 0
3 years ago
Before the last presidential debates, 50% of registered votes indicated they were planning to vote for the incumbent president.
MAVERICK [17]

Answer:

a) H₀ : p = 0.5

H_{a} : p > 0.5

b) z = 2.0785

c) p - value = 0.0188

d) Our conclusion is that there has been a significant increase in the proportion of registered voters who are planning to vote for the incumbent president

Explanation:

Probability of those planning to vote for the incumbent president before the debate, P₀ = 50/100 = 0.5

a) The null and the alternative hypothesis

Let the null hypothesis be represented by H_{0}

and the alternative hypothesis be represented by H_{a}

H₀ : p = 0.5

H_{a} : p > 0.5

b) compute the test statistics

sample size, n = 1200

number of voters planning to vote for the incumbent president, x = 636

Probability of those planning to vote for the incumbent president in the selected sample:

\bar{p} = x/n\\\bar{p} = 636/1200\\\bar{p} = 0.53

Formula for the test statistic:

z = \frac{\bar{p} - p_{0} }{\sqrt{\frac{p_{0}(1-p_{0} ) }{n} } }

z = \frac{0.53 - 0.5 }{\sqrt{\frac{0.5(1-0.5 ) }{1200} } }

z = 2.0785

c)

For \alpha = 0.05\\, the critical value as checked from the normal table will be:

z_{\alpha} = 1.645

The P value for z > 2.0785

P-value = P(z > 2.0785) \\P - value = \phi (-2.0785)\\P - value = 0.0188

d) What do you conclude?

since ( z = 2.0785) > (z_{\alpha} = 1.645), we will reject the null hypothesis.

Our conclusion is that there has been a significant increase in the proportion of registered voters who are planning to vote for the incumbent president

6 0
3 years ago
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