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sweet [91]
3 years ago
9

A triangular flag has an area of 187.5 square inches. The base of the flag measures 25 inch How tall is the triangular flag?

Mathematics
1 answer:
djyliett [7]3 years ago
3 0
To find the height, you would do the area divided by the base, or in this case,187.5 / 25 which equals 7.5 inches.  Hope this helped!
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Kirsten and Molly are on a 3-day bike ride. The entire route is 156 miles. On the first day they biked 64 miles, and on the seco
timama [110]
The distance that Kirsten and Molly need to bike on their third day is obtained by subtracting the sum of the distances they have traveled after two days from the length of the entire route.
 
                      distance left = 156 miles - (64 miles + 45 miles)
                                            = 47 miles
Thus, Kirsten and Molly need to bike 47 miles on their third day. 
3 0
3 years ago
What is the rate of change between (2,2) and (17,7)
ziro4ka [17]

Answer:

\frac{1}{3} = m

Step-by-step explanation:

\frac{-y_1 + y_2}{-x_1 + x_2} = m

\frac{-2 + 7}{-2 + 17} = \frac{5}{15} = \frac{1}{3}

I am joyous to assist you anytime.

6 0
2 years ago
The number of tourists at the beach per weekend in July was 55,000. In November, the number of tourists per weekend was 18,000.
Nonamiya [84]
55 minus 18 is 37 and then it would be 37,000 and then you just convert it so it is 37% of 100 (the answer is 37%)
6 0
3 years ago
30pts to brainlyest
snow_tiger [21]
I believe your answer is C, because Y (payment after taxes) is x (what he recieved the first time) minus taxes (0.18%) Hope this helped!
8 0
3 years ago
4.8/1 7/9 =(1.2b):6 2/3
Hunter-Best [27]

Answer:

b = 15

Step-by-step explanation:

Solve for b:

\dfrac{4.8}{1\frac{7}{9}}=\dfrac{1.2b}{6\frac{2}{3}}

Cross multiply:

6\dfrac{2}{3}\cdot 4.8=1.2b\cdot 1\dfrac{7}{9}\\ \\\dfrac{6\cdot 3+2}{3}\cdot 4.8=1.2b\cdot \dfrac{9+7}{9}\\ \\\dfrac{20}{3}\cdot \dfrac{48}{10}=\dfrac{12b}{10}\cdot \dfrac{16}{9}\\ \\20\cdot 4=b\cdot \dfrac{16}{3}\\ \\5=b\cdot \dfrac{1}{3}\\ \\b=5\cdot 3\\ \\b=15

8 0
3 years ago
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