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Orlov [11]
3 years ago
5

What are the commen factors for 60 36 48

Mathematics
2 answers:
Naddika [18.5K]3 years ago
6 0

1, 2, 3, 4, 5, 6, and 12

RoseWind [281]3 years ago
5 0
I believe that the common factors for 60, 36, and 48 are 1, 2, 3, 4, 6, and 12
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Simplify (1 − cos x)(1 + cos x).<br><br> 1<br> cos2 x<br> sin2 x<br> tan2 x
Phoenix [80]
Answer

The expression is equivalent to sin^{2}x

The first step is to multiply the two expressions between parentheses :
(II)
There is a trigonometric identity that states :

Working with this expression :
⇒
(I)
Using the equation (I) in (II) :
⇒


Read more on Brainly.com - brainly.com/question/3907632#readmore
3 0
3 years ago
Question 9
True [87]

Answer:

17

Step-by-step explanation:

m<1 = (4x + 2)

m<3 = (5x - 15)

To find the value of x, we need to generate an equation.

<1 and <3 are vertical angles. Vertical angles are congruent. Therefore:

m<1 = m<3

(4x + 2) = (5x - 15)

Use this equation to solve for x

4x + 2 = 5x - 15

Subtract 5x from both sides

4x + 2 - 5x = 5x - 15 - 5x

-x + 2 = -15

Subtract 2 from both sides

-x + 2 - 2 = -15 - 2

-x = -17

Divide both sides by -1

x = 17

5 0
2 years ago
Determine which function has the greatest rate of change over the interval [0, 2].
ruslelena [56]
Remember that the average rate of change of a function over an interval is the slope of the straight line connecting the end points of the interval. To find those slopes, we are going to use the slope formula: m= \frac{y_{2}-y_{1}}{x_2-x_1}

Rate of change of a:
From the graph we can infer that the end points are (0,1) and (2,4). So lets use our slope formula to find the rate of change of a:
m= \frac{y_{2}-y_{1}}{x_2-x_1}
m= \frac{4-1}{2-0}
m= \frac{3}{2}
m=1.5
The average rate of change of the function a over the interval [0,2] is 1.5

Rate of change of b:
Here the end points are (0,0) and (2,2)
m= \frac{2-0}{2-0}
m= \frac{2}{2}
m=1
The average rate of change of the function b over the interval [0,2] is 1

Rate of change of c:
Here the end points are (0,-1) and (2,0)
m= \frac{0-(-1)}{2-0}
m= \frac{1}{2}
m=0.5
The average rate of change of the function c over the interval [0,2] is 0.5

Rate of change of d:
Here the end points are (0,0.5) and (2,2.5)
m= \frac{2.5-0.5}{2-0}
m= \frac{2}{2}
m=1
The average rate of change of the function d over the interval [0,2] is 1

We can conclude that the <span>function that has the greatest rate of change over the interval [0, 2] is the function a.</span>
4 0
3 years ago
36 divided by 2^2 - 4 * 2 = 36 divided by ___ -4 *2<br> = ___ -4 * 2 <br> = ___ -8 <br> = ___
cricket20 [7]
2^2=4 so divid 36/4 is 9 and 4*2=8 now subtract 9-8=1 next 36/1 = 36 same on top is 8 now 36-8=28. 28 - 8 is 20 then 20-8= 12 answer is 12
6 0
2 years ago
Read 2 more answers
PLZ HELP I ONLY 15 MINS I GIVE BRAIN 5 STAR AND THX
Andre45 [30]

Answer:

A I believe

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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