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svlad2 [7]
3 years ago
9

A rectangle has an area of 21 square centimeters. Which of the following could be the rectangle's length and width? Area = lengt

h x width Choose all answers that apply
Mathematics
1 answer:
Juliette [100K]3 years ago
3 0
Width=1cm and length=21cm or width=3cm and length=7cm.
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It angle relationship and show work??
kherson [118]

Answer:

m<x=146

Step-by-step explanation:

its a supplementary angle, meaning both angles add up to 180.

So we subtract 34 from 180 which is 146.

180-34=146

5 0
3 years ago
Do you have to change the division to multiplication on a decimal?
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Example????????????????????
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Use cross products to find the area of the triangle in the xy-plane defined by (1, 2), (3, 4), and (−7, 7).
Free_Kalibri [48]

I love these. It's often called the Shoelace Formula. It actually works for the area of any 2D polygon.


We can derive it by first imagining our triangle in the first quadrant, one vertex at the origin, one at (a,b), one at (c,d), with (0,0),(a,b),(c,d) in counterclockwise order.


Our triangle is inscribed in the a \times d rectangle. There are three right triangles in that rectangle that aren't part of our triangle. When we subtract the area of the right triangles from the area of the rectangle we're left with the area S of our triangle.


S = ad - \frac 1 2 ab -  \frac 1 2 cd - \frac 1 2 (a-c)(d-b) = \frac 1 2(2 ad - ab -cd - ad +ab +cd -bc) = \frac 1 2(ad -bc)


That's the cross product in the purest form. When we're away from the origin, a arbitrary triangle with vertices A(x_1, y_1), B(x_2, y_2), C(x_3, y_3) will have the same area as one whose vertex C is translated to the origin.


We set a=x_1 - x_3, b= y_1  - y_3, c=x_2 - x_3, d=y_2- y_3


S= ad-bc=(x_1 - x_3)(y_2 - y_3) -(x_2-x_3)(y_1 - y_3)


That's a perfectly useful formula right there. But it's usually multiplied out:


S= x_1y_2 - x_1 y_3  - x_3y_2 + x_3 y_3 - x_2 y_1 + x_2y_3 + x_3 y_1 - x_3 y_3


S= x_1 y_2 - x_2 y_1  + x_2y_3 - x_3y_2   + x_3 y_1 - x_1 y_3


That's the usual form, the sum of cross products. Let's line up our numbers to make it easier.


(1, 2), (3, 4), (−7, 7)

(−7, 7),(1, 2), (3, 4),


[tex]A = \frac 1 2 ( 1(7)-2(-7) + 3(2)-4(1) + -7(4) - (7)(3)

8 0
3 years ago
Malik's solution to the equation 2/5x-4y=10 when x=60 is shown below​
Hatshy [7]

Answer:

D. Malik substituted 60 for y instead of x.

Step-by-step explanation:

3 0
3 years ago
A jogger is running home. his distance from home, as a function of time, is modeled by y=-7+8.
Dovator [93]

Answer:

y=1

Step-by-step explanation:

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