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Gennadij [26K]
3 years ago
5

We will forget this knowledge of what we learned when were older.

Mathematics
1 answer:
zlopas [31]3 years ago
6 0

Answer:

probably...but i don't think soo

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Find the area.<br> A. 19 ft²<br> B. 30 ft²<br> C. 31 ft²<br> D. 84 ft²
JulijaS [17]

Answer: D. 84 ft^2

Step-by-step explanation: The area of a trapezoid is (a+b)/2 x h. A and B are the bases, and h is the height. Plug in the numbers.

(8+16)/2 x 7 = 84

Your answer would be 84 ft^2. D.

8 0
4 years ago
Natalie paid $14.99 to join an online music service. If she purchases 9 songs each month at a cost of $0.99 per song, what will
ycow [4]

Answer:

Natalie Spent $59.54 on songs after 5 months at online music service.

Step-by-step explanation:

Total membership cost =$14.99

Number of songs purchased in each month = 9

Cost per song = $0.99

We need to find total amount she had spent after 5 months.

Solution:-

So First we will Number of songs purchased in 5 months.

1 month = 9 songs

So in 5 months = Songs purchased in 5 months.

By Using Unitary method we get;

Songs purchased in 5 months =  

Now Also Given:

1 song = $0.99

45 songs = Cost for 45 songs.

Again by using Unitary method we get;

Cost for 45 songs =  

No Total Amount Natalie spent after 5 months is equal to Total membership cost plus Cost of songs purchased in 5 months.

framing in equation form we get;

Total Amount Natalie spent =  

Hence Natalie Spent $59.54 on songs after 5 months at online music service.

5 0
3 years ago
Read 2 more answers
38)
STatiana [176]

Answer:

dbcjchdiskcnbcksksnnckdkxnn

3 0
3 years ago
Read 2 more answers
A deposit of $5,000 is made into a savings account which earns 33 4 % interest compounded annually. If no additional deposits or
S_A_V [24]
You might need cymath for that
7 0
4 years ago
Read 2 more answers
Find the laplace transform of f(t) = cosh kt = (e kt + e −kt)/2
iren2701 [21]
Hello there, hope I can help!

I assume you mean L\left\{\frac{ekt+e-kt}{2}\right\}
With that, let's begin

\frac{ekt+e-kt}{2}=\frac{ekt}{2}+\frac{e}{2}-\frac{kt}{2} \ \textgreater \  L\left\{\frac{ekt}{2}-\frac{kt}{2}+\frac{e}{2}\right\}

\mathrm{Use\:the\:linearity\:property\:of\:Laplace\:Transform}
\mathrm{For\:functions\:}f\left(t\right),\:g\left(t\right)\mathrm{\:and\:constants\:}a,\:b
L\left\{a\cdot f\left(t\right)+b\cdot g\left(t\right)\right\}=a\cdot L\left\{f\left(t\right)\right\}+b\cdot L\left\{g\left(t\right)\right\}
\frac{ek}{2}L\left\{t\right\}+L\left\{\frac{e}{2}\right\}-\frac{k}{2}L\left\{t\right\}

L\left\{t\right\} \ \textgreater \  \mathrm{Use\:Laplace\:Transform\:table}: \:L\left\{t\right\}=\frac{1}{s^2} \ \textgreater \  L\left\{t\right\}=\frac{1}{s^2}

L\left\{\frac{e}{2}\right\} \ \textgreater \  \mathrm{Use\:Laplace\:Transform\:table}: \:L\left\{a\right\}=\frac{a}{s} \ \textgreater \  L\left\{\frac{e}{2}\right\}=\frac{\frac{e}{2}}{s} \ \textgreater \  \frac{e}{2s}

\frac{ek}{2}\cdot \frac{1}{s^2}+\frac{e}{2s}-\frac{k}{2}\cdot \frac{1}{s^2}

\frac{ek}{2}\cdot \frac{1}{s^2}  \ \textgreater \  \mathrm{Multiply\:fractions}: \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d} \ \textgreater \  \frac{ek\cdot \:1}{2s^2} \ \textgreater \  \mathrm{Apply\:rule}\:1\cdot \:a=a
\frac{ek}{2s^2}

\frac{k}{2}\cdot \frac{1}{s^2} \ \textgreater \  \mathrm{Multiply\:fractions}: \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d} \ \textgreater \  \frac{k\cdot \:1}{2s^2} \ \textgreater \  \mathrm{Apply\:rule}\:1\cdot \:a=a
\frac{k}{2s^2}

\frac{ek}{2s^2}+\frac{e}{2s}-\frac{k}{2s^2}

Hope this helps!
3 0
4 years ago
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