Answer:
First option.
Step-by-step explanation:
Use the formula y = mx + b.
Where m is the slope, and b is the y-intercept.
y = -2x + 3
The slope is -2. The y-intercept is (0, 3).
It’s -4 and it’s -5.........
<span> I am assuming you want to prove:
csc(x)/[1 - cos(x)] = [1 + cos(x)]/sin^3(x).
</span>
<span>If we multiply the LHS by [1 + cos(x)]/[1 + cos(x)], we get:
LHS = csc(x)/[1 - cos(x)]
= {csc(x)[1 + cos(x)]/{[1 + cos(x)][1 - cos(x)]}
= {csc(x)[1 + cos(x)]}/[1 - cos^2(x)], via difference of squares
= {csc(x)[1 + cos(x)]}/sin^2(x), since sin^2(x) = 1 - cos^2(x).
</span>
<span>Then, since csc(x) = 1/sin(x):
LHS = {csc(x)[1 + cos(x)]}/sin^2(x)
= {[1 + cos(x)]/sin(x)}/sin^2(x)
= [1 + cos(x)]/sin^3(x)
= RHS.
</span>
<span>I hope this helps! </span>
Answer:
Yes
Step-by-step explanation:
1.2 is rational
A. left 2 units
the vertex form of a parabola is
y = a(x-h)^2 + k
(h,k) is the point of the vertex
since h is -2 in (x+2)^2
the function is shifted 2 units left
