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timurjin [86]
3 years ago
5

Michelle's mother bought 7 large pizzas for her birthday party. Each large pizza is cut into eighths. if 5/8 of the total slices

were eaten, how many slices were left over?
can you please help me with this and I will give you Brainliest.​
Mathematics
1 answer:
nirvana33 [79]3 years ago
5 0
So we know that there are 8 slices per large pizza (7), so a total of 56 slices
we would set up a proportion
5/8=x/56
8 times 7 gives you 56, and we would do that same thing to the 5 (multiply it by 7) to get 35?
so now we know that 35 out of 56 slices were eaten
56-35 is 21
so there are 21 slices left over
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Stells [14]
Think of it as a problem with only the equations so we know the exact numbers of each ride and each cost now we need to do some division and multiplication
2 games and 4 rides
6 0
3 years ago
-1.5+ (14.2) + 7.3 =​
umka21 [38]

Answer:

20

Step-by-step explanation:

<u>We are going left to right, so first:</u>

-1.5 + 14.2 = 12.7

<u>After that, we do:</u>

12.7 + 7.3

=> 20

4 0
3 years ago
The following table is for which exponential function?
sweet-ann [11.9K]
The answer is (y= 1/2)
3 0
3 years ago
Two lamps marked 100 W - 110 V and 100 W - 220 V are connected i
ELEN [110]
<h2>Answer:</h2>

The power consumed in the lamp marked 100W - 110V is 15.68W

The power consumed in the lamp marked 100W - 220V is 62.73W

<h2>Step-by-step explanation:</h2>

Given:

<em>First lamp rating</em>

Power (P) = 100W

Voltage (V) = 110V

<em>Second lamp rating</em>

Power (P) = 100W

Voltage (V) = 220V

<em>Source</em>

Voltage = 220V

i. <u>Get the resistance of each lamp</u>.

Remember that power (P) of each of the lamps is given by the quotient of the square of their voltage ratings (V) and their resistances (R). i.e

P = \frac{V^2}{R}

<em>Make R subject of the formula</em>

⇒ R = \frac{V^2}{P}             ------------------(i)

<em />

<em>For first lamp, let the resistance be R₁. Now substitute R = R₁, V = 110V and P = 100W into equation (i)</em>

R₁ = \frac{110^2}{100}

R₁ = 121Ω

<em />

<em>For second lamp, let the resistance be R₂. Now substitute R = R₂, V = 220V and P = 100W into equation (i)</em>

R₂ = \frac{220^2}{100}

R₂ = 484Ω

<em />

<em />

ii.<u> Get the equivalent resistance of the resistances of the lamps.</u>

Since the lamps are connected in series, their equivalent resistance (R) is the sum of their individual resistances. i.e

R = R₁ + R₂

R  = 121 + 484

R = 605Ω

iii. <u>Get the current flowing through each of the lamps. </u>

Since the lamps are connected in series, then the same current flows through them. This current (I) is produced by the source voltage (V = 220V) of the line and their equivalent resistance (R = 605Ω). i.e

V = IR [From Ohm's law]

I = \frac{V}{R}

I = \frac{220}{605}

I = 0.36A

iv. <u>Get the power consumed by each lamp.</u>

From Ohm's law, the power consumed is given by;

P = I²R

Where;

I = current flowing through the lamp

R = resistance of the lamp.

<em>For the first lamp, power consumed is given by;</em>

P = I²R           [Where I = 0.36 and R = 121Ω]

P = (0.36)² x 121

P = 15.68W

<em>For the second lamp, power consumed is given by;</em>

P = I²R           [Where I = 0.36 and R = 484Ω]

P = (0.36)² x 484

P = 62.73W

Therefore;

The power consumed in the lamp marked 100W - 110V is 15.68W

The power consumed in the lamp marked 100W - 220V is 62.73W

8 0
2 years ago
Which expression(s) are equivalent to -12.48 Show me how to do it pls
jeyben [28]

Answer:

djdjdjdsorry

Step-by-step explanation:

Xhshdchdjscjcchsj

7 0
2 years ago
Read 2 more answers
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