Question

The flagpole in front of VHS 50 feet tall. The angle of elevation from the end of its shadow to the top of the flagpole is 46°. what is the length of the shadow? Round your answer to the nearest foot

Answer 1

Answer:

The length of the shadow is 48.28 feet.

Step-by-step explanation:

The flagpole at its shadow form a 46, 44, 90 triangle.

Let AB be the flagpole.  AC is the shadow.

Let's use the sine law to calculate AC.

$\frac{AC}{sin(44)}=\frac{50}{sin(46)}\\AC=\sin(44)*\frac{50}{sin(46)}AC=48.28$