All categories

3 years ago

What is 3/7ths of 63

2 answers:

6 0

The best way to do this is to divide by the bottom number in the fraction and then multiply by the top one. So for example:

63 ÷ 7 = 9

9 × 3 = 27

27 is the answer

Jet001 [13]3 years ago

3 0

63: 1 x 63 3 x 21 7 x 9................

You might be interested in

Caleb is growing a plant in science class the plant grows 0.4 centimeters each week how much will the plant grow in 3 weeks

melisa1 [442]

If the plant grows 0.4 cm per week....in 3 weeks, it will have grown :
3 * 0.4 = 1.2 cm

5 0

3 years ago

The square is divided into 3 parts.

Lorico [155]

1/3= 5/15
2/5= 6/15

5/15 + 6/15 = 11/15

15/15 - 11/15 = 4/15

Part C= 4/15

4 0

3 years ago

Read 2 more answers

Directed line segment has endpoints P(– 8, – 4) and Q(4, 12). Determine the point that partitions the directed line segment in a

larisa86 [58]

Answer:

Point (1,8)

Step-by-step explanation:

We will use segment formula to find the coordinates of point that will partition our line segment PQ in a ratio 3:1.

When a point divides any segment internally in the ratio m:n, the formula is:

$[x=\frac{mx_2+nx_1}{m+n},y= \frac{my_2+ny_1}{m+n}]$

Let us substitute coordinates of point P and Q as:

$x_1=-8$ ,

$y_1=-4$

$x_2=4$

$y_2=12$

$m=3$

$n=1$

$[x=\frac{(3*4)+(1*-8)}{3+1},y=\frac{(3*12)+(1*-4)}{3+1}]$

$[x=\frac{12-8}{4},y=\frac{36-4}{4}]$

$[x=\frac{4}{4},y=\frac{32}{4}]$

$[x=1,y=8]$

Therefore, point (1,8) will partition the directed line segment PQ in a ratio 3:1.

7 0

3 years ago

At the same time a 50 ft cell phone tower casts a 32 ft shadow, a near by light pole casts a 20 ft shadow. How tall is the light

White raven [17]

Answer: 31.25 ft

Step-by-step explanation:

50 / 32 = x / 20

32x = 50(20)

x = 31.25 ft

7 0

2 years ago

How many terms are there in the sequence 1, 8, 28, 56, ..., 1 ?

BabaBlast [244]

Answer:

9 terms

Step-by-step explanation:

Given:

1, 8, 28, 56, ..., 1

Required

Determine the number of sequence

To determine the number of sequence, we need to understand how the sequence are generated

The sequence are generated using

$\left[\begin{array}{c}n&&r\end{array}\right] = \frac{n!}{(n-r)!r!}$

Where n = 8 and r = 0,1....8

When r = 0

$\left[\begin{array}{c}8&&0\end{array}\right] = \frac{8!}{(8-0)!0!} = \frac{8!}{8!0!} = 1$

When r = 1

$\left[\begin{array}{c}8&&1\end{array}\right] = \frac{8!}{(8-1)!1!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8$

When r = 2

$\left[\begin{array}{c}8&&2\end{array}\right] = \frac{8!}{(8-2)!2!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} =2 8$

When r = 3

$\left[\begin{array}{c}8&&3\end{array}\right] = \frac{8!}{(8-3)!3!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56$

When r = 4

$\left[\begin{array}{c}8&&4\end{array}\right] = \frac{8!}{(8-4)!4!} = \frac{8!}{4!3!} = \frac{8 * 7 * 6 * 5 * 4!}{4! *4*3* 2 *1} = \frac{8 * 7 * 6*5}{4*3 *2 *1} = 70$

When r = 5

$\left[\begin{array}{c}8&&5\end{array}\right] = \frac{8!}{(8-5)!5!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56$

When r = 6

$\left[\begin{array}{c}8&&6\end{array}\right] = \frac{8!}{(8-6)!6!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} = 28$

When r = 7

$\left[\begin{array}{c}8&&7\end{array}\right] = \frac{8!}{(8-7)!7!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8$

When r = 8

$\left[\begin{array}{c}8&&8\end{array}\right] = \frac{8!}{(8-8)!8!} = \frac{8!}{8!0!} = 1$

The full sequence is: 1,8,28,56,70,56,28,8,1

And the number of terms is 9

3 0

3 years ago