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Mumz [18]
3 years ago
5

Alex purchased a new car for 28,000. The cars value depreciates 7.25% each year. What will be value of the car 5 years after it

is purchased? Round your answer to the newest dollar
Mathematics
2 answers:
MrMuchimi3 years ago
8 0

Answer:

$19219.

Step-by-step explanation:

We have been given that Alex purchased a new car for 28,000. The cars value depreciates 7.25% each year.

We will use exponential decay function to solve our given problem.

y=a\cdot b^x, where,

a = Initial value,

b = For decay b is in form (1-r), where r represents decay rate in decimal form.

Let us convert our given rate in decimal form.

7.25\%=\frac{7.25}{100}=0.0725

Upon substituting our given values in above formula we will get,

y=\$28,000\cdot(1-0.0725)^5

y=\$28,000\cdot(0.9275)^5

y=\$28,000\cdot 0.686387856528418

y=\$19218.8599\approx \$19219

Therefore, the value of car 5 years after it is purchased will be $19219.

mamaluj [8]3 years ago
7 0
If depreciation is 7.25% per year, then the common factor is (1-0.0725), or 0.9275.

Thus, the car's value after 5 years will be:

V = $28000(0.9275)^5 = $28000(0.6864) = $19218.86, or (to the nearest dollar) $19218 (answer)
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Dmitriy789 [7]

Answer:

A counterexample for a conjecture is the statement that disproves a conjecture.

Step-by-step explanation:

To find : What is a counterexample for the conjecture?

Solution :

A conjecture is an educated guess but not yet proven. It is possible that next example shown the conjecture wrong.

A counterexample is an example that disproves or disagree a conjecture.

For example : Prime numbers - 3,7,11,23

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4 0
2 years ago
Use a table of function values to approximate an x-value in which the exponential function exceeds the polynomial function. In y
bekas [8.4K]
F(x) = 2^x; h(x) = x^3 + x + 8

Table


x      f(x) =  2^x             h(x) = x^3 + x + 8

0      2^0 = 1                0  + 0 + 8 = 8

1     2^1 = 2                 1^3 + 1 + 8 = 10

2      2^2 = 4                2^3 + 2 + 8 = 8 + 2 + 8 = 18

3      2^3 = 8                3^3  + 3 + 8 = 27 + 3 + 8 = 38

4      2^2 = 16              4^3 + 4 + 8 = 76

10    2^10 = 1024       10^3  +10 + 8 = 1018

 9      2^9 =   512        9^3 + 9 + 8 = 729 + 9 + 8 = 746

Answer: an approximate value of 10
7 0
2 years ago
I need help with this one
sdas [7]
I cannot see it all is their something you could do to help me help you?
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3 years ago
0.25q+0.10d=4.95<br> D=3q
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0.25q + 0.1d = 4.95
d = 3q

0.25q + 0.1(3q) = 4.95
    0.25q + 0.3q = 4.95
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                0.55     0.55
                      q = 9
0.25(9) + 0.1d = 4.95
    2.25 + 0.1d = 4.95
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3 years ago
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Answer:

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Step-by-step explanation:

I HOPE THIS HELPS ^^!!

8 0
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