For this case we have that the surface area of the prism is given by:

Where:
: Is the lateral area
B: It is the area of the base

Where:
Q: It is the perimeter of the base
h: It's the height

On the other hand:

So, we have:

Answer:

Answer:
Answer:
\{ {{20x+30y=280} \atop {y=4x}} .{
y=4x
20x+30y=280
.
Where xx is the number of small boxes sent and yy is the number of large boxes sent.
Step-by-step explanation:
Let be xx the number of small boxes sent and yy the number of large boxes sent.
Since each small box can hold 20 books (20x20x ), each large box can hold 30 books (30y30y )and altogether can hold a total of 280 books, we can write the following equation to represent this:
20x+30y=28020x+30y=280
According to the information provided in the exercise, there were 4 times as many large boxes sent as small boxes. This can be represented with this equation:
y=4xy=4x
Therefore, the system of equation that be used to determine the number of small boxes sent and the number of large boxes sent, is:
\{ {{20x+30y=280} \atop {y=4x}} .{
y=4x
20x+30y=280
.
Answer:
no
Step-by-step explanation:
Using substitution, subs in the points given
(15) = 5(4) - 2
15 = 20 - 2
Because the 2 sides are NOT equal the line would not pass through the point
1-1/6*3/2
multiply the two fractions
1/6*3/2
Cross out 3 and 6, divide by 3.
1/2 * 1/2
multiply the numerators together
1*1=1
multiply the denominators together
2*2=4
1-1/4
pretend that 1 has a denominator which is 1
1/1-1/4
find the common denominator for 1/1 which is 4
multiply by 4 for 1/1
1*4/1*4=4/4
4/4-1/4
Answer:
3/4