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3 years ago

A polygon has the following coordinates: A(-6,5), B(-1,5), C(5,3), D(-1,1), E(-6,1). Find the length of AE.

Mathematics

1 answer:

Wittaler [7]3 years ago

4 0

Answer:c

Step-by-step explanation:

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Solve the equation. Check your solution and show all your work. 2/3 h = 4

AlexFokin [52]

Answer: h=6

Step-by-step explanation:

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3 years ago

Which of the following are true statements about angle parking. Angle parking spots have a larger blind spaces than perpendicula

S_A_V [24]

Answer:

Angle parking is more common than perpendicular parking.

Angle parking spots have half the blind spot as compared to perpendicular parking spaces

Step-by-step explanation:

Considering the available options, the true statement about angle parking is that" Angle parking is more common than perpendicular parking." Angle parking is mostly constructed and used for public parking. It is mostly used where the parking lots are quite busy such as motels or public garages.

Therefore, in this case, the answer is that "Angle parking is more common than perpendicular parking."

Also, "Angle parking spots have half the blind spot as compared to perpendicular parking spaces."

5 0

2 years ago

PLZ HELP IF UR 100% SURE !!!

WARRIOR [948]

The answer is d ok dine

7 0

3 years ago

A certain bridge arch is in the shape of half an ellipse 106 feet wide and 33.9 feet high. At what horizontal distance from the

nata0808 [166]

Answer:

The horizontal distance from the center is 49.3883 feet

Step-by-step explanation:

The equation of an ellipse is equal to:

$\frac{x^2}{a^{2} } +\frac{y^2}{b^{2} } =1$

Where a is the half of the wide, b is the high of the ellipse, x is the horizontal distance from the center and y is the height of the ellipse at that distance.

Then, replacing a by 106/2 and b by 33.9, we get:

$\frac{x^2}{53^{2} } +\frac{y^2}{33.9^{2} } =1\\\frac{x^2}{2809} +\frac{y^2}{1149.21} =1$

Therefore, the horizontal distances from the center of the arch where the height is equal to 12.3 feet is calculated replacing y by 12.3 and solving for x as:

$\frac{x^2}{2809} +\frac{y^2}{1149.21} =1\\\frac{x^2}{2809} +\frac{12.3^2}{1149.21} =1\\\\\frac{x^2}{2809}=1-\frac{12.3^2}{1149.21}\\\\x^{2} =2809(0.8684)\\x=\sqrt{2809(0.8684)}\\x=49.3883$

So, the horizontal distance from the center is 49.3883 feet

8 0

3 years ago

What is the coefficient of xy2

Gre4nikov [31]

Answer:

1 is the coefficient.

There is no number Infront of variable.Hence if there is no number thrlere is 1. xysquare 1 is the coefficient,X and y are base and square is Exponent.

7 0

2 years ago