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2 years ago

Find the zeros of the quadratic function: y= 6(7x + 9)(8x - 3).

Mathematics

1 answer:

fiasKO [112]2 years ago

6 0

Answer:

A) (-9/7,0), (3/8,0)

Step-by-step explanation:

Zeros of a quadratic function:

x for which y = 0.

In this question:

$y = 6(7x + 9)(8x - 3)$

It's 0 if one of the factors is 0. 6 is never 0, now about the other to:

$7x + 9 = 0$

$7x = -9$

$x = -\frac{9}{7}$

So (-9/7, 0) is a zero of the quadratic function.

The other is:

$8x - 3 = 0$

$8x = 3$

$x = \frac{3}{8}$

(3/8,0) is the other zero.

Thus, the correct answer is given by option A.

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2 years ago

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Romashka-Z-Leto [24]

The volume of sphere is $\frac{1372}{3}\pi$ feet cubed.

Step-by-step explanation:

Given,

Surface area of sphere = 196π square feet

Surface area of sphere = 4πr²

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$\frac{4\pi r^2}{4\pi}=\frac{196\pi}{4\pi}\\\\r^2=49$

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3 years ago

Use Simpson's Rule with n = 10 to approximate the area of the surface obtained by rotating the curve about the x-axis. Compare y

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We split up the domain of integration into 10 subintervals,

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$\ell_i=\dfrac{5-0}{10}(i-1)=\dfrac{i-1}2$

$r_i=\dfrac{5-0}{10}i=\dfrac i2$

with midpoint

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with $1\le i\le10$ .

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$p_i(x)=f(\ell_i)\dfrac{(x-m_i)(x-r_i)}{(\ell_i-m_i)(\ell_i-r_i)}+f(m_i)\dfrac{(x-\ell_i)(x-r_i)}{(m_i-\ell_i)(m_i-r_i)}+f(r_i)\dfrac{(x-\ell_i)(x-m_i)}{(r_i-\ell_i)(r_i-m_i)}$

Then

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Compare this to actual value of the integral, which is closer to 1967.

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