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ololo11 [35]
3 years ago
15

What is the length of segment AD ? How do you know ?

Mathematics
1 answer:
denpristay [2]3 years ago
8 0

Line segment AD is 4cm. Because A is the center, any lines coming off the centerpoint are congruent. So if line AC is 4cm, then line AD has to be 4cm as well.

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You want to have $150,000 in your retirement account when you retire in 30 years. Your retirement account earns 7%
Arisa [49]

Answer: 123.05

Use annuity formula

3 0
3 years ago
Identifying the Graph of a System of Two-Variable Linear
vekshin1

The graph of the given system of inequalities can be seen at the end of the answer.

<h3 /><h3>How to get the graph of the system of inequalities?</h3>

Here we have the system of inequalities:

x + 3y > -3

y < 2x + 1

first, we can write both of these in the form of a line equation in the slope-intercept form.

y > (-3 - x)/3 = -1 - (1/3)*x

y < 2x + 1.

To graph this, we first need to draw the two lines as dashed lines (because the points on the lines are not solutions).

Then for the line:

y = -(1/3)*x - 1 we need to shade the region above the line (because the symbol > is used).

For the line:

y = 2x + 1

We need to shade the region below the line, because the symbol used is <.

Then the graph of the system of inequalities is the one you can see below. The solutions of the system are the ones where the two shaded regions intercept.

If you want to learn more about systems of inequalities:

brainly.com/question/9774970

#SPJ1

7 0
2 years ago
Elijah and 2 of his friends are each paid $20 per afternoon
aleksklad [387]
300 all together but 100 solo
6 0
3 years ago
Read 2 more answers
FIND THE UNIT RATE!!!!
uranmaximum [27]

Answer:

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Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Evaluate the Riemann sum for f(x) = 3x − 1, −6 ≤ x ≤ 4, with five subintervals, taking the sample points to be right endpoints.
Verdich [7]

Answer:

The Riemann sum equals -10.

Step-by-step explanation:

The right Riemann Sum uses the right endpoints of a sub-interval:

\int_{a}^{b}f(x)dx\approx\Delta{x}\left(f(x_1)+f(x_2)+f(x_3)+...+f(x_{n-1})+f(x_{n})\right)

where

\Delta{x}=\frac{b-a}{n}

To find the Riemann sum for \int\limits^{4}_{-6} {3x-1} \, dx with n = 5 rectangles, using right endpoints you must:

We know that a = -6, b = 4 and n = 5, so

\Delta{x}=\frac{4-\left(-6\right)}{5}=2

We need to divide the interval −6 ≤ x ≤ 4 into n = 5 sub-intervals of length \Delta{x}=2

a=\left[-6, -4\right], \left[-4, -2\right], \left[-2, 0\right], \left[0, 2\right], \left[2, 4\right]=b

Now, we just evaluate the function at the right endpoints:

f\left(x_{1}\right)=f\left(-4\right)=-13=-13

f\left(x_{2}\right)=f\left(-2\right)=-7=-7

f\left(x_{3}\right)=f\left(0\right)=-1=-1

f\left(x_{4}\right)=f\left(2\right)=5=5

f\left(x_{5}\right)=f(b)=f\left(4\right)=11=11

Finally, just sum up the above values and multiply by 2

2(-13-7-1+5+11)=-10

The Riemann sum equals -10

5 0
4 years ago
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