Answer: The numbers are: 16, 11 and 48
Step-by-step explanation:
Let 1st number is a, second number is b and third number is c
1st number is 5 more than the second so a=b+5
The third number is 2 times the first so c=3*a=3*(b+5)
The sum of three numbers, so a+b+c=b+5+b+3*(b+5)=75
b+5+b+3+3b+15=75
5b+20=75
5b=55
b=11
a=b+5=11+5=16
c=3*(b+5)=3*(11+5)=3*16=48
The numbers are: 16, 11 and 48
To find the right boundary, we have to add 1.5 times the IQR to Q3.
... Q3 + 1.5(Q3 -Q1) = 28 + 1.5(28 -18) = 28 +15 = 43
The right boundary is 43.
Step-by-step explanation:
I dont now but i think 20 or 34
The least distance is 1,330 yards to walk around the park once
9514 1404 393
Answer:
(4) 750 < p < 1500
Step-by-step explanation:
The total cost for p people is ...
c = 750 +2.25p
The average cost per person is this total divided by the number of people:
c/p = (750 +2.25p)/p
c/p = (750/p) +2.25
Natasha wants this to be between 2.75 and 3.25:
2.75 < c/2 < 3.25
2.75 < 750/p +2.25 < 3.25 . . . . . . use the expression for c/p
0.50 < 750/p < 1.00 . . . . . . . . . . . subtract 2.25
We can split this to two inequalities to find the limits of p.
<u>Left one</u>
0.50 < 750/p
0.50p < 750 . . .multiply by p
p < 1500 . . . . . . multiply by 2
<u>Right one</u>
750/p < 1
750 < p . . . . . . multiply by p
These bounds on p can be summarized as ...
750 < p < 1500 . . . . matches choice (4)
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<em>Additional comment</em>
Once you realize that the fixed costs will be divided by the number of people attending, the maximum cost you want ($1 more than the per-person charge) will set the minimum number of people. To have the $750 fixed cost contribute only $1 to the cost per person, there must be at least 750 people to share that cost. The only answer choice with a 750 person minimum is (4).
