Answer: No, it is not a solution. It makes the first equation true, but the second equation is false when (x,y) = (16, 1)
To check a possible solution, we replace the variable letters with their actual numbers. The given solution is (x,y) = (16,1) so x = 16 and y = 1 pair up. We'll replace x with 16, and replace y with 1.
Do so with the first equation and simplify
y = (-1/4)*x + 5
1 = (-1/4)*16 + 5
1 = -4 + 5
1 = 1 ... true
And repeat for the second equation
y = (1/6)*x - 2
1 = (1/6)*16 - 2
1 = 2.667 - 2
1 = 0.667 .... false
The equation above is false, so the original equation is false when (x,y) = (16,1). This proves the point is not on the line.
So overall, (16,1) is not a solution to the system.
We know that
[area of the figure]=[area of rectangle]+[area of semi circle]
area of rectangle=b*h------> 10*18-----> 180 cm²
area of semicircle=pi*r²/2
diameter=18 cm
radius=18/2----> 9 cm
area of semicircle=pi*9²/2-----> 127.17 cm²
[area of the figure]=[180]+[127.17]------> 307.17 cm²
round <span>to the nearest unit </span>------> 307 cm²
the answer is
the area of the figure is 307 cm²
Answer:
x<-1
Step-by-step explanation:
12x>7(4x+5)-19
<u><em>Solve the right side</em></u>
12x > 28x+35-19
12x > 28x+16
<u><em>Make x the subject</em></u>
12x-28x > 16
-16x > 16
-x > 16/16
-x > 1
Multiplying by -1 on both sides
x < -1
If you multiply ">" with minus sign, its direction changes. It is similar to switching the positions of x and -1.
<u><em>Simplify</em></u>
x < -1
The inequality of x is x<-1
Since the square is on a quadrant plane and it is a square, the fact that the lines cross in the center and start and stop in the corners allows you to tell that they are perpendicular.
So answer one is (B, D) 2 is (0, C) 3 is: 1
