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insens350 [35]
4 years ago
15

You worked 16 3/4 hours in the past two days and plan to work 12 3/4 hours in the next two days. How many hours will you total o

n your time sheet for these 4 days?.
Mathematics
2 answers:
alisha [4.7K]4 years ago
8 0
The answer is 29 and half hours is your answer 
Mars2501 [29]4 years ago
3 0
<span>You worked 16 3/4 hours for the past two days and you plan to work 12 3/4 hours in the next two days. 

16 3/4 + 12 3/4 = 28 6/4 = 29 1/2 

Therefore you worked 29 1/2 hours in the four days.</span>
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doing all 4 would help but you don't have to do all of them 2 or one is fine with me. but no fake answers
Oduvanchick [21]

Answer:

the picture is kinda blur but nvm

Step-by-step explanation:

3:b

4:b

5:a

6:b

4 0
3 years ago
SO CONFUSED PLEASE SOMEONE EXPLAIN! DUE SOON AND NEED HELP!!!!!!!! QUESTION IN PICTURE BELOW
jeka57 [31]

Answer:

=> Apply law of cosine

c^2=a^2+b^2-2abcos\left(C\right)

=> input value

z^2=6.5^2 + 9.4^2-\left(6.5\right)\left(9.4\right)\left(cos\left(131\right)\right)

=> simplify

z=\sqrt{\left(6.5^2+\:9.4^2\right)-\left(6.5\right)\left(9.4\right)\left(-0.65605902899\right)}

=> calulcation

z=\sqrt{-61.1\cos \left(131^{\circ \:}\right)+130.61},\:z=-\sqrt{-61.1\cos \left(131^{\circ \:}\right)+130.61}

=> apply rule: Distance must be greater than 0

which is about 14.51828

4 0
2 years ago
If a car factory checks 360 cars and 8 of them have defects, how many will have defects out of 1260?
viktelen [127]
You should expect 28 defected cars.
3 0
3 years ago
What is an equation of the line that passes through the point (3,-3) and is perpendicular to the line 3x+2y=12 ?
Gennadij [26K]

Answer:

y=2/3x-5

Step-by-step explanation:

1. find the slope of the given line

2. find its opposite reciprocal(slope of the perpendicular line)

3. create a new linear equation using the new slope

4. substitute (3,-3) to find b

6 0
3 years ago
Read 2 more answers
A sphere of radius r is cut by a plane h units above the equator, where
Anika [276]
Consider the top half of a sphere centered at the origin with radius r, which can be described by the equation

z=\sqrt{r^2-x^2-y^2}

and consider a plane

z=h

with 0. Call the region between the two surfaces R. The volume of R is given by the triple integral

\displaystyle\iiint_R\mathrm dV=\int_{-\sqrt{r^2-h^2}}^{\sqrt{r^2-h^2}}\int_{-\sqrt{r^2-h^2-x^2}}^{\sqrt{r^2-h^2-x^2}}\int_h^{\sqrt{r^2-x^2-y^2}}\mathrm dz\,\mathrm dy\,\mathrm dx

Converting to polar coordinates will help make this computation easier. Set

\begin{cases}x=\rho\cos\theta\sin\varphi\\y=\rho\sin\theta\sin\varphi\\z=\rho\cos\var\phi\end{cases}\implies\mathrm dx\,\mathrm dy\,\mathrm dz=\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi

Now, the volume can be computed with the integral

\displaystyle\iiint_R\mathrm dV=\int_0^{2\pi}\int_0^{\arctan\frac{\sqrt{r^2-h^2}}h}\int_{h\sec\varphi}^r\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\varphi\,\mathrm d\theta

You should get

\dfrac{2\pi}3\left(r^3\arctan\dfrac{\sqrt{r^2-h^2}}h-\dfrac{h^3}2\left(\dfrac{r\sqrt{r^2-h^2}}{h^2}+\ln\dfrac{r+\sqrt{r^2-h^2}}h\right)\right)
5 0
3 years ago
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