The area of the regular heptagon which has a radius of approximately 27.87 cm and the length of each side is 24.18 cm is 2125 cm².
<h3>What is the area of a heptagon?</h3>
Heptagon is the closed shape polygon which has 7 sides and 7 interior angles.
The area of the regular heptagon is found out using the following formula.

Here, (<em>a</em>) is the length of the heptagon.
A regular heptagon has a radius of approximately 27.87 cm and the length of each side is 24.18 cm. Put the value of side in the above formula,

Hence, the area of the regular heptagon which has a radius of approximately 27.87 cm and the length of each side is 24.18 cm is 2125 cm².
Learn more about the area of a heptagon here;
brainly.com/question/26271153
Answer:
The total surface area of a solid is the sum of the areas of all of the faces or surfaces that enclose the solid, the lateral surface area of a solid is the surface area of the solid without the bases
Answer:
Step-by-step explanation:
10 = r²h
(2r)²(2h) = 16r²h
volume of B is 1.6 times the volume of A
Given:
The system of inequalities is:


To find:
The graph of the given system of inequalities.
Solution:
We have,


The related equations are:


Table of values for the given equations is:

0 1 -3
3 0 3
Plot (0,1) and (3,0) and connect them by a straight line to get the graph of
.
Similarly, plot (0,-3) and (3,3) and connect them by a straight line to get the graph of
.
The signs of both inequalities are ">". So, the boundary line is a dotted line and the shaded region or each inequality lie above the boundary line.
Therefore, the graph of the given system of inequalities is shown below.