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3 years ago

I need help on this question?

Mathematics

2 answers:

tatiyna3 years ago

8 0

Answer:

the square root of 36 is greater that the square root of -8

Step-by-step explanation:

The square root of 36 is 6

The square root of -8 is 2.82842712 i

hope this answers your question.

iris [78.8K]3 years ago

3 0

Answer:

it is bigger than -8 (>)

Step-by-step explanation:

the square root of 36 is 6 which is bigger than -8

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(1)Kamlesh brought a juice bottle of 5 litres. He drank 214 litres

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Answer:

I think there is a typing error it should be 214 ml

Step-by-step explanation:

1 litre = 1000 ml

5 litre= 5000ml

5000- 214= 4786

hope it helps :)

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3 years ago

Which of the following appear in the diagram below?

NeTakaya

Answer: Please provide the diagram.

Step-by-step explanation:

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Which of the following represents the factorization of the binomial below ? X2-121

nataly862011 [7]

Answer:

(x+11)(x-11)

Step-by-step explanation:

A ^2 - B ^2 =(A+B) (A-B).. (*)

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3 years ago

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Solve these linear equations in the form y=yn+yp with yn=y(0)e^at.

WINSTONCH [101]

Answer:

a) $y(t) = y_{0}e^{4t} + 2$ . It does not have a steady state

b) $y(t) = y_{0}e^{-4t} + 2$ . It has a steady state.

Step-by-step explanation:

a) $y' -4y = -8$

The first step is finding $y_{n}(t)$ . So:

$y' - 4y = 0$

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

$r - 4 = 0$

$r = 4$

So:

$y_{n}(t) = y_{0}e^{4t}$

Since this differential equation has a positive eigenvalue, it does not have a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

$y_{p}(t) = C$

$(y_{p})' -4(y_{p}) = -8$

$(C)' - 4C = -8$

C is a constant, so (C)' = 0.

$-4C = -8$

$4C = 8$

$C = 2$

The solution in the form is

$y(t) = y_{n}(t) + y_{p}(t)$

$y(t) = y_{0}e^{4t} + 2$

b) $y' +4y = 8$

The first step is finding $y_{n}(t)$ . So:

$y' + 4y = 0$

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

$r + 4 =$

$r = -4$

So:

$y_{n}(t) = y_{0}e^{-4t}$

Since this differential equation does not have a positive eigenvalue, it has a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

$y_{p}(t) = C$

$(y_{p})' +4(y_{p}) = 8$

$(C)' + 4C = 8$

C is a constant, so (C)' = 0.

$4C = 8$

$C = 2$

The solution in the form is

$y(t) = y_{n}(t) + y_{p}(t)$

$y(t) = y_{0}e^{-4t} + 2$

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3 years ago

Tyson brought a bag of coins into the bank to be counted. The bag contained only nickels and

podryga [215]

There will be 130 nickels and 90 dimes. 100 nickels is 5 dollars. 90 dimes are 9 dollars. And then there will be 30 left. 30 dimes isn’t 1.50$ bur 30 nickels is 1.50$ so you add the 30 to the nickels and it’ll be exactly 15.50$.

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3 years ago