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Natali [406]
3 years ago
12

jll invited 37 people to her birthday party they each ate 8 pieces of pizza how many pieces of pizza did they eat

Mathematics
1 answer:
Molodets [167]3 years ago
8 0
If Jill invited 37 people to her party, there will be a total of 38 people there. If each 38 people had 8 pieces of pizza, you would multiply 38 with 8, which the answer will be 304. They ate 304 pieces of pizza.
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Help pls I'll give 25 points
RideAnS [48]

Answer:

\text{C. }60

Step-by-step explanation:

<u>Question from image</u>:

"The digits 1, 2, 3, 4, and 5 can be formed to arrange 120 different numbers. How many of these numbers will have the digits 1 and 2 in increasing order? For example, 14352 and 51234 are two such numbers."

Let's start by taking a look with the number 1. There are four possible places 1 could be, because there needs to be space for the 2 after it.

Checkmarks mark where the 1 can be, the <em>x</em> marks where it cannot be.

\underline{\checkmark}\:\underline{\checkmark}\:\underline{\checkmark}\:\underline{\checkmark}\:\underline{X}

Let's start with the first position:

\underline{\checkmark}\:\underline{\#}\:\underline{\#}\:\underline{\#}\:\underline{\#}

There are four places the 2 can be. For each of these four places, we can arrange the remaining 3 digits in 3!=6 ways. Therefore, there are 4\cdot 6=\boxed{24} possible numbers when 1 is the first digit of the number.

Continue this process with the remaining possible positions for 1.

Second position:

\underline{X}\underline{\checkmark}\:\underline{\#}\:\underline{\#}\:\underline{\#}

There are three places the 2 can be, since the 2 must be behind the 1. For each of these three places, the remaining 3 digits can be arranged in 3!=6 ways. Therefore, there are 3\cdot 6=\boxed{18} possible numbers when 1 is the second digit of the number.

The pattern continues. Next there will be 2 places to place the 2. For each of these, there are 3!=6 ways to rearrange the remaining 3 digits for a total of 2\cdot 6=\boxed{12} possible numbers when 1 is the third digit of the number.

Lastly, when 1 is the fourth digit of the number, there is only 1 place the 2 can be. For this one place, there are still 3!=6 ways to rearrange the remaining three numbers. Therefore, there are 1\cdot 6=\boxed{6} possible numbers when 1 is the fourth digit of the number.

Thus, there are 24+18+12+6=\boxed{60} numbers that will have the digits 1 and 2 in increasing order, from a set of 120 five-digit numbers created by the digits 1 through 5, where no digit may be repeated.

5 0
3 years ago
Is (-7,3) a solution to this inequality? Y- 4x &lt; - 5. Show your work or describe what you did to decide the answer.
satela [25.4K]
No because (-7, 3) is like (x, y)
Plug and chug [what I call it] into the equation
(3) - 4(-7) < 5
3- (-28)<5
31<5 <—— this is not true so it would be galse
8 0
3 years ago
Write an equation in point-slope form of the line having the given slope that contains the given point. then graph the line
alexira [117]
The point-slope equation would be
y = 1/8x + 3/4
3 0
3 years ago
Read 2 more answers
Use long division:<br> 3x2 + 2x-5<br> 3x-1
uysha [10]
This is the answer just open it.

5 0
3 years ago
Read 2 more answers
HELP ME PLZ
GarryVolchara [31]

Answer:

(-1,3)

Step-by-step explanation:

Thus;

When (-1,3) is placed in the relation 3x + y =0,the answer will be zero.

<h3>Calculations</h3>

Let;

x= -1

y= 3

3(-1) + 3 =0

-3 + 3 = 0

5 0
3 years ago
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