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omeli [17]
4 years ago
14

A particle decays at a rate of 0.45% annually. assume and initial amount of 300 mg. (

Mathematics
1 answer:
raketka [301]4 years ago
6 0
The increase is an exponential increase in a multiplier
100%+0.45%=100.45% and as decimal 1.0045

Final Value = Initial Value × multiplier^{number of years}
Final value = 300(1.0045)^{60}
Final value = 393 mg (to the nearest whole number)

Half life = 0.5 years
Final value = 300(1.0045)^{0.5}=301 mg
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Commuting. there are two routes he could take to work. Aneighbor who has lived there a long time tells him Route Awill average 5
iren2701 [21]

Answer:

a)We are 95% confident that the average commuting time for route A is between 1.3577 and 4.6423 minutes shorter than the average committing time for rout B.  

(b) No, because the confidence internal does not contain —5, which corresponds with an average of 5 minutes shorter for route A.

Step-by-step explanation:

Given:  

n_1 = 20

x_1= 40

s_1 = 3

n_2 = 20

x_2= 43

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d_f = 33.1

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(a) Determine the t-value by looking in the row starting with degrees of freedom df = 33.1 > 32 and in the column with c = 95% in the Student's t distribution table in the appendix:  

t\alpha/2 = 2.037  

The margin of error is then:  

E = t\alpha/2 *√s_1^2/n_1+s_2^2/n_2

E = 2.037  *√3^2/20+s_2^2/20

  = 1.64

The endpoints of the confidence interval for u_1 — u_2 are:  

(x_1 — x_2) — E = (40 — 43) — 1.6423 = —3 — 1.6423= —4.6423

(x_1 - x_2)  + E   = (40 — 43) + 1.6423 = —3 + 1.6423= —1.3577  

a)We are 95% confident that the average commuting time for route A is between 1.3577 and 4.6423 minutes shorter than the average committing time for rout B.  

(b) No, because the confidence internal does not contain —5, which corresponds with an average of 5 minutes shorter for route A.

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3 years ago
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SOVA2 [1]

Answer:

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Step-by-step explanation:

0.9

4 0
4 years ago
1/3 (x – 10) = -4, x =
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Answer:

Step-by-step explanation:

Divide both sides by 1/3, which is equivalent to mulitplying by 3

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x = -2

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3 years ago
0.2(x + 1) + 0.5x = –0.3(x – 4)
pashok25 [27]
X=1 im pretty sure :)
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