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netineya [11]
3 years ago
8

On a Saturday a library check out 66 books and if 18 of the books were fiction what is the ratio of nonfiction books to fiction

books checked out
Mathematics
2 answers:
dalvyx [7]3 years ago
8 0
66 - 18 = 48
Nonfiction : Fiction
48 : 18
Divide both by 6
8 : 3
Anika [276]3 years ago
5 0
First I did the 18 fiction-66 the book totals and I got 48 and then i put it in ratio 48:18 that was my answer
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Kieth ran a marathon. It took 3 hours and 2 mins to run 26 miles. If he ran at the same rate for the whole race, how many minute
baherus [9]
It took him 7 minutes to run each mile.

Firstly, covert the time into minutes.
3 * 60 = 180 minutes 
180 + 2 = 182 minutes

Now in order to find how long he ran each mile,
divide 182 by 26
182/26 = 7 minutes
7 0
3 years ago
1140 was rounded to the nearest ten.<br>What is the upper bound?<br>​
zloy xaker [14]

Answer:

1145

Step-by-step explanation:

  • <em>The upper bound is the smallest value that would round up to the next estimated value</em>.

Since the number was rounded to nearest ten, the upper bound is:

  • 1145

which rounds up to 1150 which is the next estimated value greater than 1140

8 0
3 years ago
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rafeal counted a total of 40 white cars and yellow cars. there were 9 times as many white cars as yellow cars. how many white ca
liberstina [14]
360 is the anwer because i multipled 40 white cars by 9 times yellow car to get answer 40×9=360
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3 years ago
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pentru a asorta pernele cu sfoara, aura coase fiecareia , pe margini pamblica albastra. cati cm sunt necesari ? rezolva intrun s
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6 0
3 years ago
A 4 metre ladder is placed against a vertical wall.
Black_prince [1.1K]

Answer:

Original position: base is 1.5 meters away from the wall and the vertical distance from the top end to the ground let it be y and length of the ladder be L.

Step-by-step explanation:

By pythagorean theorem, L^2=y^2+(1.5)^2=y^2+2.25 Eq1.

Final position: base is 2 meters away, and the vertical distance from top end to the ground is y - 0.25 because it falls down the wall 0.25 meters and length of the ladder is also L.

By pythagorean theorem, L^2=(y -0.25)^2+(2)^2=y^2–0.5y+ 0.0625+4=y^2–0.5y+4.0625 Eq 2.

Equating both Eq 1 and Eq 2: y^2+2.25=y^2–0.5y+4.0625

y^2-y^2+0.5y+2.25–4.0625=0

0.5y- 1.8125=0

0.5y=1.8125

y=1.8125/0.5= 3.625

Using Eq 1: L^2=(3.625)^2+2.25=15.390625, L=(15.390625)^1/2= 3.92 meters length of ladder

Using Eq 2: L^2=(3.625)^2–0.5(3.625)+4.0625

L^2=13.140625–0.90625+4.0615=15.390625

L= (15.390625)^1/2= 3.92 meters length of ladder

<em>hope it helps...</em>

<em>correct me if I'm wrong...</em>

4 0
3 years ago
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