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Ksivusya [100]
3 years ago
8

After the party, there was 0.5 of the pizza left. Angela ate 0.2 of the leftover pizza.

Mathematics
1 answer:
Gwar [14]3 years ago
4 0
Nobody has the correct answer
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PLEASE ANSWER QUICK: How do you find the distance between two points on a number line when the units are variables.
9966 [12]

If we want to find the distance between two points on a number line use the distance formula:


6 0
2 years ago
Read 2 more answers
Corey spends 16% of his salary on food each week. If his salary is $800 per week, how much does Corey spend on food each week?
Flura [38]

Answer:

128

Step-by-step explanation:

16% of 800 is 128

7 0
2 years ago
a job offer with a starting salary with $ 35,600 and a guaranteed raise of $ 1200 per year for the next 5 years. what is the tot
ra1l [238]
He'll make $41,600 by the sixth year
6 0
3 years ago
A group of 8 people are picking up litter along a 4 over 5 km length of road. Each person is assigned an equal section of the ro
zepelin [54]

You know that 1 km=1000 m, then the length of the road \dfrac{4}{5} km is \dfrac{1000}{5} \cdot 4=200\cdot 4=800 metres.

A group of 8 people are picking up litter along the road and each person is assigned an equal section of the road. The whole road has length 800 m, then for each person will be assigned 800:8=100 m of the road.

If you want to know the length of each part in km, then 1 m=0.001 km and 100 m =1 m·100=0.001 km ·100=0.1 km.

5 0
2 years ago
Look at this cylinder:
Sedbober [7]
  • Height=h=8cm
  • Radius=r=4cm

We know

\boxed{\sf \star TSA_{(Cylinder)}=2\pi r(h+r)}

\\ \sf\longmapsto TSA_{(Old\:Cylinder)}=2\times \dfrac{22}{7}\times 4(8+4)

\\ \sf\longmapsto TSA_{(Old\:Cylinder)}=\dfrac{176}{7}(12)

\\ \sf\longmapsto TSA_{(Old\:Cylinder)}=\dfrac{2112}{7}

\\ \sf\longmapsto TSA_{(Old\:Cylinder)}=301.7cm^2

Now

  • New Radius=2(4)=8cm
  • New Height=2(8)=16cm

\\ \sf\longmapsto TSA_{(New\:Cylinder)}=2\times \dfrac{22}{7}\times 8(16+8)

\\ \sf\longmapsto TSA_{(New\:Cylinder)}=\dfrac{352}{7}(24)

\\ \sf\longmapsto TSA_{(New\:Cylinder)}=\dfrac{8448}{7}

\\ \sf\longmapsto TSA_{(New\:Cylinder)}=1204.7cm^2

So

\\ \sf\longmapsto \dfrac{TSA_{(New\:Cylinder)}}{TSA_{(Old\:Cylinder)}}=\dfrac{1204.7}{301.7}

\\ \sf\longmapsto \dfrac{TSA_{(New\:Cylinder)}}{TSA_{(Old\:Cylinder)}}=\dfrac{4}{1}

\\ \sf\longmapsto\underline{\boxed{\bf{ {TSA_{(New\:Cylinder)}}:{TSA_{(Old\:Cylinder)}}=4:1}}}

Hence our correct option is Option C

6 0
2 years ago
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