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3 years ago

Order the steps to solve the equation Log(x^2-15)=log(2x) form 1 to 5.

Mathematics

2 answers:

sleet_krkn [62]3 years ago

4 0

Answer:

x2 − 15 = 2x
x2 − 2x − 15 = 0
(x − 5)(x + 3) = 0
x − 5 = 0 or x + 3 = 0
Potential solutions are −3 and 5

Zarrin [17]3 years ago

3 0

Step 1: x²-15=2x
step 2: x²-2x-15=0
step 3: (x-5)(x+3)=0
step 4: x-5=0 or x+3=0
step 5: x=5 of x=-3

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If equal amounts are added to the numerator and the denominator of the current ratio, the ratio will always:

Marta_Voda [28]

Answer:

Increase?

Step-by-step explanation:

Because think about it let's use 1/2 as an example.

1/2 equals .5 now lets add 2 to both the numerator and denominator

3/4 is the result and it also equals .75 which is larger than .5 so that's why the answer is increase.

and u can keep on going on with the method

4/5=.8

7 0

3 years ago

Please solve 3x≤−5/4

frosja888 [35]

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3 years ago

40% of the students in a school are boys. lf there are 240 boys, how many student are therein the school?

Stells [14]

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3 years ago

What number raised to the -2 exponent would equal 1/4?

serious [3.7K]

Let, the number = x
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Hope this helps!

5 0

3 years ago

Find the price-demand equation for a particular brand television when the demand is 20 TVs per week at $150 per TV, given that t

Alina [70]

Answer:

~ $150=50e^{-0.01()20}$

~ $p(100)=\$127.7$

Step-by-step explanation:

From the question we are told that:

Price of 20TVs per week $P_{20}=\$150$

Marginal price-demand function $p'(x)=-0.5e-0.01x$

Generally the The Marginal price function is mathematically given by

$p'(x)=-0.5e^{-0.01x}$

$p(x)=\int-0.5e^{-0.01x}$

$p(x)=50e^{-0.001x}+C$

Therefore the equation when the demand is 20 TVs per week at $150 per TV

$150=50e^{-0.01()20}$

Giving

$p(x)=50e^{-0.01x}+150-50e^{-0.01(20)}$

Therefore the Price when the demand is 100 TVs per week

$p(100)=50e^{-0.01(100)}+150-50e^{-0.01(20)}$

$p(100)=\$127.7$

7 0

2 years ago