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zheka24 [161]
4 years ago
10

What is the answer for 3,4,5,6 and 7?

Mathematics
1 answer:
EastWind [94]4 years ago
4 0
#3- five cans is $3.50 so if you do 350+350 you come out to seven dollars for 10 cans so the village market would be cheaper
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Suppose MNP & QRS. If m
lilavasa [31]
Is this a question that needs answered or free points?
7 0
3 years ago
For the experiment described, write the indicated event in set notation.
pentagon [3]

Answer:

d. {(1,2),(2,2),(3,2),(4,2),(5,2),(6,2)}

Step-by-step explanation:

First one can be any of the six outcomes

7 0
4 years ago
A) <br> 1<br> 4<br> B) <br> 1<br> 8<br> C) <br> 1<br> 12<br> D) <br> 1<br> 16
vitfil [10]

Answer:

The answer is below.

Step-by-step explanation:

3 0
3 years ago
Why is C the answer for this question?
Grace [21]

Step-by-step explanation:

A left Riemann sum approximates a definite integral as:

\int\limits^b_a {f(x)} \, dx \approx \sum\limits_{k=1}^{n}f(x_{k}) \Delta x \\where\ \Delta x = \frac{b-a}{n} \ and\ x_{k}=a+\Delta x \times (k-1)

Given ∫₂⁸ cos(x²) dx:

a = 2, b = 8, and f(x) = cos(x²)

Therefore, Δx = 6/n and x = 2 + (6/n) (k − 1).

Plugging into the sum:

∑₁ⁿ cos((2 + (6/n) (k − 1))²) (6/n)

Therefore, the answer is C.  Notice that answer D would be a right Riemann sum rather than a left (uses k instead of k−1).

8 0
4 years ago
HELPPP!!!
spayn [35]

Answer:

  A. see below for a graph

  B. f(x, y) = f(0, 15) = 90 is the maximum point

Step-by-step explanation:

A. See below for a graph. The vertices are those defined by the second inequality, since it is completely enclosed by the first inequality: (0, 0), (0, 15), (10, 0)

__

B. For f(x, y) = 4x +6y, we have ...

  f(0, 0) = 0

  f(0, 15) = 6·15 = 90 . . . . . the maximum point

  f(10, 0) = 4·10 = 40

_____

<em>Comment on evaluating the objective function</em>

I find it convenient to draw the line f(x, y) = 0 on the graph and then visually choose the vertex point that will put that line as far as possible from the origin. Here, the objective function is less steep than the feasible region boundary, so vertices toward the top of the graph will maximize the objective function.

8 0
3 years ago
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