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2 years ago

9

Three bags of flour and two bags of sugar wait 32 pounds four bags of sugar wait 32 pounds all bags of flour wait to save it all

back to sugar wait to say what is the ratio of the weight of bag of flour two with bag of sugar

1 answer:

Contact [7]2 years ago

3 0

You worded this weird, but each bag of sugar is 8 pounds...

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Which expression is equivalent to cot t sec t?

Solnce55 [7]

Answer: $csc(t)$

Step-by-step explanation:

Alright, lets get started.

The given expression is given as :

$cot( t) \times sec (t)$

We know quotient identity as :

$cot(t)=\frac{cos(t)}{sin(t)}$

Similarly, we know reciprocal identity as :

$sec(t)=\frac{1}{cos(t)}$

lets plug the value of cot and sec in given expression

$\frac{cos(t)}{sin(t)} \times \frac{1}{cos(t)}$

cos will be cancelled, remaining will be

$\frac{1}{sin(t)}$

Using reciprocal identity again, that will equal to :

$csc(t)$ ................... Answer (A)

8 0

2 years ago

The Rachel’s daily expenses for 10 days are in the table.

Annette [7]

The correct answer is $44.20.
If we add up all the tips, the total is $442. If we divide this by the number of days (10), then we find the mean.
442 / 10 = 44.2

4 0

2 years ago

Mark thinks the equation y=6x+4 will match the red solid graph. Mia thinks it will match the blue dotted graph. Who’s right? Exp

Rudiy27

Answer:

Technically neither, but Mia is correct.

Step-by-step explanation:

Slope-Intercept Form: y = mx + b

Since our slope <em>m</em> is equal to 6, it is a positive number. That means that the slope/line will be positive, so the line should be going up, not down. That means the blue line would be correct. Therefore, Mia is correct.

Technicality:

Since the blue line is dotted, the equation should be a <em>inequality </em>and not a linear equation. No solutions on the line would technically work. If the equation was y < 6x + 4 or something with an inequality sign, then it would be correct.

6 0

2 years ago

The Resource Conservation and Recovery Act mandates the tracking and disposal of hazardous waste produced at U.S. facilities. Pr

aniked [119]

Answer:

(a) $E(X) = 0.383$

The expected number in the sample that treats hazardous waste on-site is 0.383.

(b) $P(x = 4) = 0.000169$

There is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

Step-by-step explanation:

Professional Geographer (Feb. 2000) reported the hazardous waste generation and disposal characteristics of 209 facilities.

N = 209

Only eight of these facilities treated hazardous waste on-site.

r = 8

a. In a random sample of 10 of the 209 facilities, what is the expected number in the sample that treats hazardous waste on-site?

n = 10

The expected number in the sample that treats hazardous waste on-site is given by

$E(X) = \frac{n \times r}{N}$

$E(X) = \frac{10 \times 8}{209}$

$E(X) = \frac{80}{209}$

$E(X) = 0.383$

Therefore, the expected number in the sample that treats hazardous waste on-site is 0.383.

b. Find the probability that 4 of the 10 selected facilities treat hazardous waste on-site

The probability is given by

$P(x = 4) = \frac{\binom{r}{x} \binom{N - r}{n - x}}{\binom{N}{n}}$

For the given case, we have

N = 209

n = 10

r = 8

x = 4

$P(x = 4) = \frac{\binom{8}{4} \binom{209 - 8}{10 - 4}}{\binom{209}{10}}$

$P(x = 4) = \frac{\binom{8}{4} \binom{201}{6}}{\binom{209}{10}}$

$$ P(x = 4) = \frac{70 \times 84944276340}{35216131179263320}$

$P(x = 4) = 0.000169$

Therefore, there is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

8 0

2 years ago

If it is sunday when you cross the international date line while traveling westward, the next day is

mixas84 [53]

You cross the date line into Monday.

_____
The next day after Monday is Tuesday. (I find it difficult to tell the intent of the question.)

3 0

2 years ago