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RoseWind [281]
3 years ago
15

What are the slope and the y-intercept of the linear function that is represented by the table?

Mathematics
1 answer:
natka813 [3]3 years ago
6 0
Slope is 2/5 and the y into is -1/3

I just went with the slope. So I am not sure about the y-int.

Slope= y2 -y1 over x2-x1

(-2/15–1/30) =-.1
—————————- (over)
(-1/2- -3/4) =. -.75

- 0.1 / - 0.25 = .4 = 2/5
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Simplify -5( -2n - 6) + n<br><br> FAST I SUCK AT MATH!!!!
loris [4]
The answer is 11n + 30
5 0
3 years ago
Ten more than 6 times a number is 4 less than 4 times the number
Leona [35]
Answer: -7

Form your equation. Let x be the number.
6x + 10 = 4x - 4

Solve.
6x + 10 = 4x - 4               Subtract 4x from both sides
2x + 10 = -4                     Subtract 10 from both sides
2x = -14                           Divide by 2 to both sides
x = -7                               Answer!

8 0
4 years ago
A gas cylinder contains 1.00 mol He, 1.90 mol Ne, and 1.10 mol Ar. If the total pressure in the cylinder is 2250 mmHg, what is t
Tcecarenko [31]

Answer:

P_he = 562.5 mmHg

P_ne = 1068.75 mmHg

P_ar = 618.75 mmHg

Step-by-step explanation:

Formula for partial pressure is;

Partial pressure = mole fraction × total pressure

Mole fraction of Helium(He); x_he= 1/(1 + 1.9 + 1.1) = 1/4 = 0.25

Mole fraction of Neon(Ne); x_ne = 1.9/(1 + 1.9 + 1.1) = 1.9/4 = 0.475

Mole fraction of argon; x_ar = 1.1/(1 + 1.9 + 1.1) = 1.1/4 = 0.275

Thus;

Partial pressure of He;

P_he = 0.25 × 2250

P_he = 562.5 mmHg

Partial pressure of Ne;

P_ne = 0.475 × 2250

P_ne = 1068.75 mmHg

Partial pressure of Ar;

P_ar = 0.275 × 2250

P_ar = 618.75 mmHg

5 0
3 years ago
Which statements about functions g(x) = x2 - 4x + 3 and f(x) = x2 - 4x are true? Select all that apply.
Tanya [424]

Answer:

A and B

Step-by-step explanation:

We are given that

g(x)=x^2-4x+3

g(x)=(x^2-2\times x\times 2+4)-4+3=(x-2)^2-1

Compare with it

y=(x-h)^2+k

Where vertex=(h,k)

We get

Vertex of g=(2,-1)

f(x)=x^2-4x=(x^2-2\times x\times 2+4)-4=(x-2)^2-4

Vertex of f=(2,-4)

Equation of axis of symmetry=x-coordinate of vertex

Axis of symmetry of g

x=2

Axis of symmetry of f

x=2

Differentiate w.r.t x

g'(x)=2x-4=0

2x-4=0\implies 2x=4

x=\frac{4}{2}=2

f'(x)=2x-4

2x-4=0\implies 2x=4

x=\frac{4}{2}=2

g''(x)=2>0

f''(x)=2>0

f and g have both minima at x=2

Hence, option A and B are true.

8 0
4 years ago
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