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2 years ago

Riddle what 3D shape should be afraid of?

Mathematics

2 answers:

Goshia [24]2 years ago

8 0

Answer:

sphere

Step-by-step explanation:

Digiron [165]2 years ago

4 0

Well a sphere ok ok :)

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Polygons ABCD and A'B'C'D' are shown on the following coordinate grid:A coordinate grid is shown from positive 6 to negative 6 o

Blababa [14]

A(2, -2), B(4, -2), C(1, -3), D(5, -3).

A'(1, 2), B'(1, 4), C'(2, 1), D'(2, 5)

That looks like a rotation 90 degrees around the origin then a translation.

Let's do the rotation ABCD->A"B"C"D"

The rotation is (x,y)->(-y,x)

A"(2, 2), B"(2,4), C"(3,1), D"(3,5).

Compare to

A'(1, 2), B'(1, 4), C'(2, 1), D'(2, 5)

we need to translate one unit to the left.

Answer: 90 degree rotation around the origin then translation by (-1,0)

5 0

2 years ago

Read 2 more answers

Stephanie is 20 years old and has a base annual premium of 930 and a rating factor of 1.30. what is her total premium?

fredd [130]

Don't listen to the other guy. The ANSWER is A). 1209. Your welcome!

5 0

3 years ago

A manufacturing company has two retail outlets. It is known that 30% of all potential customers buy

aleksandrvk [35]

Answer:

(a) A y P(A) = 0.4 (b) $\bar{B}$ y $P(\bar{B})$ =0.5 (c) $\bar{A}$ ∪ $\bar{B}$ y P( $\bar{A}$ ∪ $\bar{B}$ ) = 0.9 (d) $\bar{A}$ ∩ $\bar{B}$ y P( $\bar{A}$ ∩ $\bar{B}$ )=0.2

Step-by-step explanation:

A was defined as the event that a potential customer, randomly chosen, buys from outlet 1 in the original problem statement. We know that B denotes the event that a randomly chosen customer buys from outlet 2. So

P( $A\cap \bar{B}$ ) = 0.3, P( $B\cap \bar{A}$ ) = 0.4 and P( $A\cap B$ ) = 0.1

(a) P(A) = P( $A\cap (B\cup\bar{B})$ ) = P( $A\cap B$ ) + P( $A\cap \bar{B}$ ) = 0.1 + 0.3 = 0.4

(b) P(B) = P( $B\cap (A\cup\bar{A})$ ) = P( $B\cap A$ ) + P( $B\cap \bar{A}$ ) = 0.1 + 0.4 = 0.5

P( $\bar{B}$ ) = 1-P(B) = 1-0.5 = 0.5

(c) The customer does not buy from outlet 1 is the complement of A, i.e., $\bar{A}$ , and the customer does not buy from outlet 2 is the complement of B, i.e., $\bar{B}$ , so, the customer does not buy from outlet 1 or does not buy from outlet 2 is $\bar{A}$ ∪ $\bar{B}$ and P( $\bar{A}$ ∪ $\bar{B}$ ) = P( $(A\cap B)^{c}$ ) by De Morgan's laws

P( $(A\cap B)^{c}$ ) = 1-P(A∩B)=1-0.1=0.9

(d) The customer does not buy from outlet 1 is the complement of A, and the customer does not buy from outlet 2 is the complement of B, so we have that the statement in (d) is equivalent to $\bar{A}$ ∩ $\bar{B}$ and P( $\bar{A}$ ∩ $\bar{B}$ ) = P( $(AUB)^{c}$ ) by De Morgan's laws, and

P( $(AUB)^{c}$ ) = 1-P(A∪B)=1-[P(A)+P(B)-P(A∩B)]=1-[0.4+0.5-0.1]=1-0.8=0.2

8 0

2 years ago

Write 7.5^{1.25} as a radical

Paul [167]

Answer:

sushi and the cousin that pushed it back to you are you answering my phone calls for you to come over and watch the game Player Wins the answer is Abiotic the answer is Abiotic the answer is Abiotic the answer is Abiotic the answer is Abiotic the answer is Abiotic the beginning and only one the answer is that a museum the answer to play with you and I will vanish the same time I don't think so epic in a bit if you edited it and

Step-by-step explanation:

<h2>FUN FACT : I WROTE THESE USING AUTO CORRECT</h2>

5 0

2 years ago

Read 2 more answers

Find all complex solutions of X^2-5X -5= 0

denis-greek [22]

ANSWER

$x = \frac{ 5 - 3\sqrt{ 5} }{2} \: or \: x = \frac{ 5 +3 \sqrt{ 5} }{2}$