Answer:
[2 5 0]
[-7 -11/2 12]
Step-by-step explanation:
We want to perform elementary row operation represented by R2 - ½R1 on matrix A in the figure attached.
Now, matrix A is given as;
[2 5 0]
[-6 -3 12]
Now, R1 is row 1 = [2 5 0]
R2 is row 2 = [-6 -3 12]
Thus, R2 - ½R1 = [-6 -3 12] - ½[2 5 0]
This gives;
[-6 -3 12] - [1 5/2 0] = [-7 -11/2 12]
Now,[-7 -11/2 12] will be the new row 2 since it's just an elementary row operation we did on the Matrix A.
Thus, the new matrix is now;
[2 5 0]
[-7 -11/2 12]
Answer:
the length = eleven meters.
Step-by-step explanation:
area divided by width.
33/3 = 11.
Step-by-step explanation:
Note that t = d/r where t is time, d is distance, and r is rate/speed.
We can come up with two equations with the information given and the equation:
t_1 hr = (10 km)/(x km/hr)
t_2 hr = (12 km)/(x - 1 km/hr)
<em>where t_1 is the time taken to run the 10km the first day and t_2 is the time taken to run the 12km the second day.</em>
We know that 30 minutes is 1/2 of an hour and that t_1 is 30 minutes less than t_2 (as stated in the question). Therefore, we can write:
t_1 = t_2 - 1/2
Substituting the values we derived:
(10 km)/(x km/hr) = (12 km)/(x - 1 km/hr) -1/2
Then we can evaluate by multiplying by 2x(x-1) on both sides:
20(x-1) = 24x - (x)(x-1)
20x - 20 = 24x - x^2 + x
x^2 -5x -20 = 0
And we are done.
I hope this helps! :)
This needs to be 20 characters long but it’s 4/3
Answer:
i cant see the picture
Step-by-step explanation:
