Answer: The father is 37 years and the son is 7 years
Step-by-step explanation:
Let x represent the present age of the father.
Let y represent the present age of the son.
Three years hence a father will four times as old as his son will be. This means that
x + 3 = 4(y + 3)
x + 3 = 4y + 12
x - 4y = 12 - 3
x - 4y = 9- - - - - - - - - - - - - - - -1
Before two years he was seven times as old as his son was. This means that
(x - 2) = 7(y - 2)
x - 2 = 7y - 14
x - 7y = - 14 + 2
x - 7y = - 12- - - - - - - - - - - - - - -2
Subtracting equation 2 from equation 1, it becomes
3y = 21
y = 21.3 = 7
Substituting y = 7 into equation 1, it becomes
x - 4 × 7 = 9
x - 28 = 9
x = 9 + 28
x = 37
Answer:
105
Step-by-step explanation:
15*6=90
6*5=30
30/2=15
90+15=105
I think the answer is: -3/7x
Answer:
1) f
4 * ¼ = 1 (Multiplicative inverse property)
2) c
6 * 1 = 6 (Identity property of multiplication)
3) h
5 + 7 = 7 + 5 (Commutative property of addition)
4) j
If 5 + 1 = 6 and 4 + 2 = 6, then 5 + 1 = 4 + 2 (Transitive property)
5) a
4(x - 3) = 4x - 12 (Distributive property)
6) i
3(5) = 5(3) (Commutative property of multiplication)
7) k
Rules that allow us to take short cuts when solving algebraic problems.(Properties)
8) d
5 * (3 * 2) = (5 * 3) * 2 (Associative property of multiplication)
9) g
4 + (-4) = 0 (Additive inverse property)
10) e
2 + 0 = 2 (Identity property of addition)
11) b
A + (B + C) = (A + B) + C (Associative property of addition)
The value of 6 is 6 hundreths
