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Margarita [4]
3 years ago
9

Triangle A C B is cut by line segment E D. Line segment E D goes from side B C to side A C. The length of B A is 4 x minus 6 and

the length of E D is x + 2. The length of B E is x. Sides B E and E C are congruent. Sides A D and D C are congruent. We can apply the triangle midsegment theorem: ED = One-halfBA. Evaluate the equation for x. What is the length of BC? a 5 b 6 c 10 d 2.5
Mathematics
2 answers:
Marina CMI [18]3 years ago
4 0

Answer:

the answers are

D

Triangle midsegment

5

10

Step-by-step explanation:

leva [86]3 years ago
3 0

Answer:

D

Triangle Midsegment

5

10

Step-by-step explanation:

Got it right on the assignment on EDG2020 :)

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In the expansion (ax+by)^7, the coefficients of the first two terms are 128 and -224, respectively. Find the values of a and b
madam [21]

Answer:

a = 2, b = 3.5

Step-by-step explanation:

Expanding (ax+by)^7 using Binomial expansion, we have that:

(ax+by)^7 =

(ax)^7(by)^0 + (ax)^6(by)^1 + (ax)^5(by)^2 + (ax)^4(by)^3 + (ax)^3(by)^4 + (ax)^2(by)^5 + (ax)^1(by)^6 + (ax)^0(by)^7

= (a)^7(x)^7+ (a)^6(x)^6(b)(y) + (a)^5(x)^5(b)^2(y)^2 + (a)^4(x)^4(b)^3(y)^3 + (a)^3(x)^3(b)^4(y)^4 + (a)^2(x)^2(b)^5(y)^5 + (a)(x)(b)^6(y)^6 + (b)^7(y)^7\\\\\\= (a)^7(x)^7+ (a)^6(b)(x)^6(y) + (a)^5(b)^2(x)^5(y)^2 + (a)^4(b)^3(x)^4(y)^3 + (a)^3(b)^4(x)^3(y)^4 + (a)^2(b)^5(x)^2(y)^5 + (a)(b)^6(x)(y)^6 + (b)^7(y)^7

We have that the coefficients of the first two terms are 128 and -224.

For the first term:

=> a^7 = 128

=> a = \sqrt[7]{128}\\ \\\\a = 2

For the second term:

a^6b = -224

b = \frac{-224}{a^6}

b = \frac{-224}{2^6} \\\\\\b = \frac{-224}{64} \\\\\\b = 3.5

Therefore, a = 2, b = 3.5

5 0
3 years ago
Evaluate : f(x) = x^2 - 2x + 1 , x = 3
den301095 [7]

Answer:

4

Step-by-step explanation:

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Answer:

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5 0
3 years ago
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Alja [10]

Answer:

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Step-by-step explanation:

y = mx + b

where m = slope and b = y-intercept.

The value of m is 3/4. That means slope is 3/4. Changing 3/4 to - 3/4 will make the slope become negative. Therefore the answer is B.

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