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Margarita [4]
3 years ago
9

Triangle A C B is cut by line segment E D. Line segment E D goes from side B C to side A C. The length of B A is 4 x minus 6 and

the length of E D is x + 2. The length of B E is x. Sides B E and E C are congruent. Sides A D and D C are congruent. We can apply the triangle midsegment theorem: ED = One-halfBA. Evaluate the equation for x. What is the length of BC? a 5 b 6 c 10 d 2.5
Mathematics
2 answers:
Marina CMI [18]3 years ago
4 0

Answer:

the answers are

D

Triangle midsegment

5

10

Step-by-step explanation:

leva [86]3 years ago
3 0

Answer:

D

Triangle Midsegment

5

10

Step-by-step explanation:

Got it right on the assignment on EDG2020 :)

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ok done. Thank to me :>

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Which of the following whole numbers is even?
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Give the equation of the line perpendicular to y +7= -2(x - 6) through the<br> point (6,-3)
lilavasa [31]

<u>Note: this answer assumes the equation of the line can be put in slope-intercept form. </u>

Answer:

y + 3 = \frac{1}{2}(x-6)

Step-by-step explanation:

1) First, find the slope of y + 7 = -2 (x - 6). We can see that it's already in point-slope form, or y-y_1 = m (x-x_1) format. Remember that the number in place of the m is the slope. Therefore, -2 is the slope of that equation.

What we need is the slope that is perpendicular to that, though. So, find the opposite reciprocal of -2. To do this, change its sign, convert it into a fraction (-\frac{2}{1}), and flip its numerators and denominators. Therefore, the perpendicular slope would be \frac{1}{2}.

2) Now that we have a slope and a point the line passes through, we can write an equation using the point-slope formula, y-y_1 = m (x-x_1). In order to write an equation, the x_1, y_1, and m have to be substitute for with real values.

The m represents the slope. We already calculated that in the last step, so put \frac{1}{2} in place of the m. The x_1 and y_1 represent the x and y values of a point the line passes through. We know that the line has to pass through (6, -3), so substitute 6 for x_1 and -3 for y_1:

y - (-3) = \frac{1}{2}(x -(6))\\y + 3 = \frac{1}{2}(x - 6)

Therefore, (again, assuming that the line can be put in point-slope form) the answer is y + 3 = \frac{1}{2}(x-6).

5 0
3 years ago
in efg, m angle e = 30 degrees, m angle f =60 degrees and m to the angle g= 90 degrees which o the statements about efg are true
Dimas [21]

well I can’t see the statements but I would say it is a right triangle

5 0
3 years ago
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