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Darina [25.2K]
3 years ago
11

P(x)=2x^2+4x+2please say the answer fast I have an activity​

Mathematics
1 answer:
LenaWriter [7]3 years ago
5 0

Answer:

(-1,0)

Step-by-step explanation:

To find the x value of the vertex use the equation

-b/(2a)

-4/(2*2)= -1

this means that the x coordinate is -1

Now that we know the x value we need to find the corresponding y value

to do this we just plug in x into the equation

2(-1)²+4(-1)+2

2-4+2=0

put it all together and get (-1,0)

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Two 5-year girls, Alyse and Jocelyn, have been training to run a 1-mile race. Alyse's 1 mile time A is approximately Normally di
tatyana61 [14]

Answer:

1.7 × 10⁻⁴

Step-by-step explanation:

The question relates to a two sample z-test for the comparison between the means of the two samples  

The null hypothesis is H₀:  μ₁ ≤ μ₂

The alternative hypothesis is Hₐ: μ₁ > μ₂

z=\dfrac{(\bar{x}_1-\bar{x}_2)-(\mu_{1}-\mu _{2} )}{\sqrt{\dfrac{\sigma_{1}^{2} }{n_{1}}-\dfrac{\sigma _{2}^{2}}{n_{2}}}}

Where;

\bar {x}_1 = 13.5

\bar {x}_2 = 12

σ₁ = 2.5

σ₂ = 1.5

We set our α level at 0.05

Therefore, our critical z = ± 1.96

For n₁ = n₂ = 23, we have;

z=\dfrac{(13.5-12)-(0)}{\sqrt{\dfrac{2.5^{2} }{23}-\dfrac{1.5^{2}}{23}}} = 3.5969

We reject the null hypothesis at α = 0.05, as our z-value, 3.5969 is larger than the critical z, 1.96 or mathematically, since 3.5969 > 1.96

Therefore, there is enough statistical evidence to suggest that Alyse time is larger than Jocelyn in a 1 mile race on a randomly select day and the probability that Alyse has a larger time than Jocelyn is 0.99983

Therefore;

The probability that Alyse has a smaller time than Jocelyn is 1 - 0.99983 = 0.00017 = 1.7 × 10⁻⁴.

8 0
3 years ago
TRUE or FALSE; Quadratic Equations' graphs take the form of V's.
Whitepunk [10]

Answer:

False, they take form of a U shape

6 0
3 years ago
a grocery store earns 5% on all canned goods. if the store sold $1635 of canned goods, what was the profit?
Likurg_2 [28]

Answer: $817.50

Step-by-step explanation: i did maths

6 0
4 years ago
The volumes of two similar figures are given. The surface area of the larger figure is given. Find the surface area of the small
frez [133]

Answer:

surface area of the smaller figure ≈ 1474.64 m²

Step-by-step explanation:

The figures are similar base on the question . The surface area and the volume of the larger figure is given while only the figure of the smaller figure is given.

To find the surface area of the smaller figure we simply use the ratios. That is the scale factors.

Therefore, they are similar figure the scale factor  can be represented as a:b.

The scale factor for volume is cubed.

volume of larger figure/volume of the small figure = a³/b³

4536/2625 = a³/b³

a/b = 16.5535451/13.7946209

Note that for two similar solid with scale factor a:b the surface area ratio is a²: b² (the scale factor is square)

16.55²/13.79² = 2124/x

273.9025/190.1641 = 2124/x

cross multiply

273.9025x = 403908.54840

x = 403908.54840/273.9025

x = 1474.6435261

x ≈ 1474.64 m²

4 0
3 years ago
Liam babysat for 3 1/2 hours and made $31.50. How much money does he make per hour?
anzhelika [568]

Answer:

$9 per hour

Step-by-step explanation:

31.50/3.5 = 3150/350 = 630/70 = 63/7 = 9

Hope this helps!      :3

plz mark as brainliest!

5 0
3 years ago
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