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lapo4ka [179]
3 years ago
12

Triangle ABC has 2 known sides. A = 7, b = 5. Angle C = 24.63. What is the value of side c, correct to one decimal place?

Mathematics
1 answer:
Elis [28]3 years ago
5 0
We use the Law of Cosines:
side c² = a² + b² -2ab • cos(C)
side c^2 = 7^2 + 5^2 -(2*7*5*cosine(24.63))
side c^2 = 49 + 25 -(70 * 0.90902)
side c^2 = 74 - <span> <span> <span> 63.6314 </span> </span> </span>
side c^2 = <span> <span> <span> 10.3686 </span> </span> </span>
side c = <span> <span> <span> 3.22

Source:
http://www.1728.org/trigtut2.htm

</span></span></span>
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Triangle FGH with vertices F(6,6), G(8,8), and H(8,3): (a) Reflection: in the line x = 5 (b) Translation: (x,y)→ (x - 7, y - 9)
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(a) The vertices after the reflection in the line x = 5 are F'(4,6) , G'(2,8) , H'(2,3) .

and (b) after translation , the vertices are F''(-1,-3) , G'' (1,-1) , H''(1,-6) .

In the question a triangle FGH with vertices F(6,6) , G(8,8) and H(8,3) is given

Part (a)

the rule for reflection of point (x,y) by the line x = p  is

(x,y) → (2×p - x , y)

reflection by the line x = 5 ,

we get

the vertices as

F'(2×5-6,6) = (4,6)

G'(2×5-8,8) = (2,8)

H'(2×5 - 8 ,3) = (2,3)

Part (b)

the rule of translation is given as (x,y)→ (x - 7, y - 9)

So , the vertices after translation are

F''(6-7 , 6-9) = (-1,-3)

G''(8-7,8-9) = (1,-1)

H''(8-7,3-9) = (1,-6)

Therefore , (a) The vertices after the reflection in the line x = 5 are F'(4,6)

G'(2,8) , H'(2,3) .

and (b) after translation , the vertices are F''(-1,-3) , G'' (1,-1) , H''(1,-6) .

Learn more about Translation here

brainly.com/question/3456459

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