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lapo4ka [179]
3 years ago
12

Triangle ABC has 2 known sides. A = 7, b = 5. Angle C = 24.63. What is the value of side c, correct to one decimal place?

Mathematics
1 answer:
Elis [28]3 years ago
5 0
We use the Law of Cosines:
side c² = a² + b² -2ab • cos(C)
side c^2 = 7^2 + 5^2 -(2*7*5*cosine(24.63))
side c^2 = 49 + 25 -(70 * 0.90902)
side c^2 = 74 - <span> <span> <span> 63.6314 </span> </span> </span>
side c^2 = <span> <span> <span> 10.3686 </span> </span> </span>
side c = <span> <span> <span> 3.22

Source:
http://www.1728.org/trigtut2.htm

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