3x - y + z = 5 . . . (1)
x + 3y + 3z = -6 . . . (2)
x + 4y - 2z = 12 . . . (3)
From (2), x = -6 - 3y - 3z . . . (4)
Substituting for x in (1) and (3) gives
3(-6 - 3y - 3z) - y + z = 5 => -18 - 9y - 9z - y + z = 5 => -10y - 8z = 23 . . (5)
-6 - 3y - 3z + 4y - 2z = 12 => y - 5z = 18 . . . (6)
(6) x 10 => 10y - 50z = 180 . . . (7)
(5) + (7) => -58z = 203
z = 203/-58 = -3.5
From (6), y - 5(-3.5) = 18 => y = 18 - 17.5 = 0.5
From (4), x = -6 - 3(0.5) - 3(-3.5) = -6 - 1.5 + 10.5 = 3
x = 3, y = 0.5, z = -3.5
Answer:
x = 2 , y = 11
Step-by-step explanation:
the diagonals of a parallelogram bisect each other , then
PT = TR , that is
y = 5x + 1 → (1)
QT = TS , that is
2y = 6x + 10 → (2)
substitute y = 5x + 1 into (2)
2(5x + 1) = 6x + 10
10x + 2 = 6x + 10 ( subtract 6x from both sides )
4x + 2 = 10 ( subtract 2 from both sides )
4x = 8 ( divide both sides by 4 )
x = 2
substitute x = 2 into either of the 2 equations for corresponding value of y
substituting into (1)
y = 5(2) + 1 = 10 + 1 = 11
Answer:
3x^2y\sqrt(y)
Step-by-step explanation:
(\sqrt() means square root
its the 2nd one
Find the number that both can be divided by i.e. the common denominator of 56/8 is 8 because 56 is divisible by 8 and 8 is also divisible by 8.
so by finding the common denominator and dividing the fraction, the equation would look like this: 7/1
